Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 18)
18.
What is the voltage across the capacitor in the given circuit?
Discussion:
8 comments Page 1 of 1.
Shania said:
8 years ago
What happen if the components are connected in parallel?
Lakshmi said:
1 decade ago
Not every time voltage magnification occurs depends is it leading or lagging current condition.
Apoorva said:
1 decade ago
Because in series RLC circuits there is voltage magnification across reactive components.
Afash said:
1 decade ago
How it is possible that voltage across a capacitor is greater than source voltage?
Nagamallareddy said:
1 decade ago
Due to voltage magnification voltage across capacitor greater than Source voltage.
All options are less than 20v except D.
All options are less than 20v except D.
Mohit said:
1 decade ago
Is there any short trick to solve such question. Because this process is time consuming in PSU exam?
Clara said:
1 decade ago
Reactance of inductor XL=2*pi*f*L ==> 2*3.14*800*25m ==> 125.66
Reactance of capacitor XC=[1/(2*pi*f*C)] ==> 1/(2*3.14*800*0.47u)==>423.28
Z= sqrt(R^2+(XL-XC)^2) ; I=V/Z;
substituting for Z=370.1
substituting for I=20/370.1 = 54.04mA
Finally Vc=I*XC ==> 22.87
Reactance of capacitor XC=[1/(2*pi*f*C)] ==> 1/(2*3.14*800*0.47u)==>423.28
Z= sqrt(R^2+(XL-XC)^2) ; I=V/Z;
substituting for Z=370.1
substituting for I=20/370.1 = 54.04mA
Finally Vc=I*XC ==> 22.87
(1)
Hussain said:
1 decade ago
Vc = I * Xc;
Xc = 1/(2*pi*f*c);
I = V/Z; V = 20 given
Z = sqrt(R2 + (XL-XC)2);
Xc = 1/(2*pi*f*c);
I = V/Z; V = 20 given
Z = sqrt(R2 + (XL-XC)2);
(1)
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