Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 21)
21.
What is the true power consumed in a 30 V series RLC circuit if Z = 20 ohms and R = 10 ohms?
Discussion:
14 comments Page 1 of 2.
Marvin said:
4 years ago
G = Re(Z) = R/Z^2 = 0.025 Ohm;
Active power dissipates only on active resistance (conductivity)
P = U^2G = 30^2 * 0.025 = 22.5 W.
Active power dissipates only on active resistance (conductivity)
P = U^2G = 30^2 * 0.025 = 22.5 W.
(1)
Satish said:
7 years ago
Thanks @Vishal.
Dhaval pujara said:
8 years ago
Here given,
V = 30v
Z = 20ohms
I = v/z
I=??
Then,
True power(p) = i^2*r.
V = 30v
Z = 20ohms
I = v/z
I=??
Then,
True power(p) = i^2*r.
Simi said:
9 years ago
True power= I^2 * R.
Reactive Power = I^2 * X.
Apparent Power = I^2 * Z.
Here, I = V/Z = 30 / 20 = 3/2.
True power =(3/2)^2 * 10 = 22.5W.
Reactive Power = I^2 * X.
Apparent Power = I^2 * Z.
Here, I = V/Z = 30 / 20 = 3/2.
True power =(3/2)^2 * 10 = 22.5W.
(1)
RAHUL KUSHWAHA said:
9 years ago
@Ram Mohan, your answer is perfectly right. Thanks.
Hriday said:
9 years ago
@Neeraja.
z itself includes r so, do not solve to zt.
z is already given and the z value is used to calculate the current whereas r is used to calculate the power.
z itself includes r so, do not solve to zt.
z is already given and the z value is used to calculate the current whereas r is used to calculate the power.
Amritpal singh said:
1 decade ago
Then why the answer is not coming by p = I2R = VI = 30*1.5 = 45.
Basitsheikh said:
1 decade ago
@Vishal your answer is very smart and authentic.
Afash said:
1 decade ago
Friends Remember one thing. When the value of Z given in RLC ctk it means that the total R of the circuit is Z. as like:
Z= sqrt of R^2 + (Xl -Xc)^2.
So there is no need to find Resistance of the ckt.
Just like:
I = v/Z.
1.5 A.
Than T.Power = I^2 *R.
So you will get the answer.
Z= sqrt of R^2 + (Xl -Xc)^2.
So there is no need to find Resistance of the ckt.
Just like:
I = v/Z.
1.5 A.
Than T.Power = I^2 *R.
So you will get the answer.
Akshay said:
1 decade ago
Circuit current = v/z = 30/20 = 3/2.
True power = vicos (theta).
Where cos (theta) = r/z = 10/20 = 5/10.
True power = 30*3/2*5/10 = 22.5w.
True power = vicos (theta).
Where cos (theta) = r/z = 10/20 = 5/10.
True power = 30*3/2*5/10 = 22.5w.
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