Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 21)
21.
What is the true power consumed in a 30 V series RLC circuit if Z = 20 ohms and R = 10 ohms?
Discussion:
14 comments Page 2 of 2.
Vishal said:
1 decade ago
I=V/Z.
I=30/20=1.5.
P=I^2*R.
P=2.25*10=22.5W.
I=30/20=1.5.
P=I^2*R.
P=2.25*10=22.5W.
Ram mohan said:
1 decade ago
Because circuit impedence =20 ohm
So current in circuit = v/z = 30/20 = 1.5 amp
True power = I^2XR = (1.5)^2 X 10 = 22.5 Watt
So current in circuit = v/z = 30/20 = 1.5 amp
True power = I^2XR = (1.5)^2 X 10 = 22.5 Watt
Anjay pal said:
1 decade ago
@Neeraja your calculation is wrong.
Zt=sqrt(Z2+R2)
Zt=sqrt{(20)2+(10)2}, =sqrt(400+100),=sqrt(500),
zt=22.36ohms
It=V/Zt
It=30/22.36
It=1.34amps
true power=It2*R
(1.34)2*10
1.7956*10
17.95W
But this wrong answer.
Zt=sqrt(Z2+R2)
Zt=sqrt{(20)2+(10)2}, =sqrt(400+100),=sqrt(500),
zt=22.36ohms
It=V/Zt
It=30/22.36
It=1.34amps
true power=It2*R
(1.34)2*10
1.7956*10
17.95W
But this wrong answer.
Neeraja said:
1 decade ago
Zt=sqrt(z2+R2) where Zt equals to around 20.2
Zt = 20.2ohms
V= 30v
It=V/Zt= 1.5amps
R = 10ohms
true Power = It2*R
(1.5)2* 10
2.25*10
22.5W
Zt = 20.2ohms
V= 30v
It=V/Zt= 1.5amps
R = 10ohms
true Power = It2*R
(1.5)2* 10
2.25*10
22.5W
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