Electronics - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
What is the bandwidth of the circuit?

31.8 Hz
32.3 Hz
142 Hz
7.2 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 2 of 4.

Laurent p .Eranga said:   10 years ago
First find fr = 1/6.28 times square root of LC.

You will got 71.2 hz.

Then find xl = 6.28 times fl you will got 2.23 k if xl = xc.

Then q = xl/r you will got 2.23 k/1 k = 2.235.

If the formula for bw = fr/q.

fr = 71.2 and q = 2.235 so bw = fr/q will be equals to 31.8 hz.

Vijay said:   8 years ago
Q=(omega*L)/R.
BW=f/Q,
=> BW=(f*R)/(w*L)
=> BW=R/(2*pi*L)
=> Bw=31.8.

Daks said:   1 decade ago
Easy way.

BW = Fr/Q
BW = 1/2*pi*L/R
BW = R/2*pi*L
BW = 31.83

Ayush Purwar said:   8 years ago
Bandwidth= R/(2*L)...Hz.
= 1000/(2*3.14*5).
= 31.84 Hz.

SUMA said:   7 years ago
Here, R/(2*π*L) = 31.8.

PRITAM said:   5 years ago
Q=XL/R.
BW=fr/Q.
fr=1/2*pi*√LC=71.17.
XL=WL=2235.87,
Q=XL/R=2.23.
B=71.17/2.23=31.83.

Abdullah said:   4 years ago
The bandwidth formula can be rearranged to R/(2*π*L).

Bogart said:   6 months ago
fr = QBW.
BW = fr/Q.
fr = 1/2π √LC..
Q=(1/R)(√ of L/C).

LALIT GARG said:   1 decade ago
As Q=B.W/fr
so fr=1/(2pie*underroot of LC)
And Q=UNDERROOT OF L/(R*UNDERROOT OF C)
B.W=?

Shah said:   1 decade ago
B' = R/L in radians.
B' = 1000/5.
B' = 200.
B = B'/2*pi.
B = 200/2*pi.
B = 31.83.


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