Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 41)
41.
What is the power factor?


Discussion:
14 comments Page 1 of 2.
Neeraja Pamala said:
1 decade ago
Power Factor = True Power/Apparent Power
Vandana said:
1 decade ago
@Neeraja
please tell me,how the answer can be evaluated using this formula.
please tell me,how the answer can be evaluated using this formula.
Deep said:
1 decade ago
pf=R/Z
Minu vaishnavi said:
1 decade ago
For parallel RLC circuit powerfactor=(truepower)/(apparentpower)
True power (Pr)=Ir^2*R
Apparent power (Pa)=Vs*It
P.F=(Ir^2*R)/(Vs*It)
True power (Pr)=Ir^2*R
Apparent power (Pa)=Vs*It
P.F=(Ir^2*R)/(Vs*It)
Gasim said:
1 decade ago
z=sqrt(R^2+(xl-xc)^2)
i=vs/z
p=i^2*R
P.F=P/(vs*i)
i=vs/z
p=i^2*R
P.F=P/(vs*i)
Shawn said:
1 decade ago
In previous question, we have calculated phase angle -28.5.
And Power Factor = cos(@).
Therefore ..cos (28.5) = 0.879.
Option D?
And Power Factor = cos(@).
Therefore ..cos (28.5) = 0.879.
Option D?
Vaishnavi said:
1 decade ago
Iz = sqrt (Ir^2+Ix^2) = 0.1411 A.
Z = E/Iz = 497/0.1411 = 3522.3 ohm.
True power = Ir^2*R = 61.702 W.
App power = Iz^2*Z = 70.126 W.
Power factor = 61.702/70.126
= 0.879.
Z = E/Iz = 497/0.1411 = 3522.3 ohm.
True power = Ir^2*R = 61.702 W.
App power = Iz^2*Z = 70.126 W.
Power factor = 61.702/70.126
= 0.879.
Abhiee said:
10 years ago
I'm also getting 0.879. What is the correct answer and solution for this problem? please mention.
Murugan said:
7 years ago
In parallel rlc circuit.
Z=1/√((1÷r)^2+(1÷xl-1÷xc)^2).
i=v/z.
Power factor=true power/apparent power.
True power=i^2*r.
Apparent power=Vs * i.
Therefore power factor=i^2*r/Vs*i.
@Gasim your formula is a series circuit.
Z=1/√((1÷r)^2+(1÷xl-1÷xc)^2).
i=v/z.
Power factor=true power/apparent power.
True power=i^2*r.
Apparent power=Vs * i.
Therefore power factor=i^2*r/Vs*i.
@Gasim your formula is a series circuit.
Alvin said:
7 years ago
I Can't get this. Please, someone, explain in clear.
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