Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 41)
41.
What is the power factor?
Discussion:
14 comments Page 2 of 2.
Arun sundar said:
6 years ago
Use PF=Z/R for the parallel circuit.
(1)
Pritam said:
5 years ago
Agree @Arun Sundar.
PF=z/R is working.
PF=z/R is working.
Pritam said:
5 years ago
PF= R/Z (for series).
pF= Z/R (for Parallel).
pF= Z/R (for Parallel).
Kalvs said:
2 years ago
For true power P, I used V^2/R /= 497^2/4k = 61.75 W.
Apparent Power, I used V^2/Z = 497^2/3516 = 70.23 VA.
Pf = P/S (real power/apparent power) = 61.75/70.23 = 0.879.
Apparent Power, I used V^2/Z = 497^2/3516 = 70.23 VA.
Pf = P/S (real power/apparent power) = 61.75/70.23 = 0.879.
(1)
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