Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - True or False (Q.No. 12)
12.
The total power dissipated is 4.8 watts.
Discussion:
22 comments Page 1 of 3.
Teja said:
1 decade ago
Find total current from supply by applying current division rule at parallel resistors. After finding total curr multiply it by 48v to get total power.
Viswam said:
1 decade ago
In any resistive ckt the total power supplied by voltage source must be dissipated across the resistors in that network.
Viswam said:
1 decade ago
By using network reduction techniques calculate parellel resistance and calculate the power supplied by source by using v*v/r it must be equall to dissipated power.
Rakesh kumar jakhar said:
1 decade ago
Use Formula I=V/R I-Current V-Voltage R- Resistance
Jignesh Rathod said:
1 decade ago
R=603 ohm
V=48 V
The total power dissipated = V*V/R
=48*48/603
=3.82
V=48 V
The total power dissipated = V*V/R
=48*48/603
=3.82
Deepak sharma said:
1 decade ago
v*v/r =48*48/603 =3.82
Monica said:
1 decade ago
Power Dissipated = V^2/R
=48*48/603
=3.82
=48*48/603
=3.82
Rekha said:
1 decade ago
How do you calculate total Resistance? please explain any body
Venkatesh said:
1 decade ago
How should we calculate resistance?
Atmi said:
1 decade ago
If R1, R2 are connected in series, then total resistance = R1+R2.
If they are connected in parallel, total resistance = (R1*R2) / (R1+R2).
If they are connected in parallel, total resistance = (R1*R2) / (R1+R2).
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