Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - True or False (Q.No. 12)
12.
The total power dissipated is 4.8 watts.

True
False
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 2 of 3.

Raji said:   1 decade ago
In the above circuit which resistors are in series and which are in parallel ?

How to find it ?

Vivek Singh said:   1 decade ago
All Resistors are in parallel. Because The current divide in each branch and voltage across all resistor are same.

Ameen said:   1 decade ago
If the two leads of resistor is connected to the leads of another one. Then we can say that resistors are in parallel.

Knight said:   1 decade ago
Total Resistance = 1 / [(1/R1) + (1/R2) + (1/R3 + ....) ].

Deepanshi yadav said:   1 decade ago
Firstly calculate the equation resistance then current through circuit by ohms law, then finally we can calculate power by p=vi or by p=i^2/r.

Utkarsh said:   1 decade ago
How could resistance be 603?

Itishree said:   10 years ago
1/R = 199/120.

R = 120/199 = 0.6030150754 Kohm.

= 603.01 ohm.

It is approximately equal to 603 ohm.

P = VI = V*V/R.

= 48*48/603.

= 3.820895.

Ashok said:   10 years ago
Please said 1/R = 199/120. How should we calculate it?

Yogesh said:   10 years ago
How 603 is calculated please explain?

Ruby said:   10 years ago
Current through 1000 Ohms = 48/1000 = 0.048.
Current through 3000 Ohms = 48/3000 = 0.016.
Current through 5000 Ohms = 48/5000 = 0.0096.
Current through 8000 Ohms = 48/8000 = 0.0796.

Total Current is 0.0796 mA Therefore power dissipated is 0.0796 mA*48V = 3.8208.
(1)


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