Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)
2.
What is the product-over-sum result of 150 and 6800?
Discussion:
17 comments Page 2 of 2.
Vijay said:
1 decade ago
r1=150,r2=6800
r1*r2=1020000
r1+r2=6950
(r1*r2)/(r1+r2)=1020000/6950
=146.76
r1*r2=1020000
r1+r2=6950
(r1*r2)/(r1+r2)=1020000/6950
=146.76
RAVI KUMAR K V said:
1 decade ago
R = R1R2/R1+R2.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
Sweety amuru said:
10 years ago
R = 1/R1 + 1/R2 then R = R1R2/R1+R2.
R = 150*6800/150+6800.
R = 147.76.
R = 150*6800/150+6800.
R = 147.76.
(1)
Vikas said:
1 decade ago
This is law of parallel addition of resistance.
R = r1*r2/r1+r2 = 146.7
R = r1*r2/r1+r2 = 146.7
Jadav said:
6 years ago
product = 6800*150,
Sum = 6800+150,
Ans = product/ sum = 146.7.
Sum = 6800+150,
Ans = product/ sum = 146.7.
(2)
Raushan said:
9 years ago
50*6800/(150+6800) = 1020000/6950 = 146.7626.
(1)
VIDYANAND BHARTI said:
1 decade ago
R{EQ)=R1*R2 /R1+R2 =150*6800/150+6800=146.7
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