Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)
2.
What is the product-over-sum result of 150 and 6800?
Discussion:
17 comments Page 1 of 2.
Jadav said:
6 years ago
product = 6800*150,
Sum = 6800+150,
Ans = product/ sum = 146.7.
Sum = 6800+150,
Ans = product/ sum = 146.7.
(2)
B.Ramya said:
8 years ago
Product over sum = product/sum = (r1*r2)/(r1+r2).
= (150 * 6800)/(150+6800)
= 1020000/6950.
= 146.76258993 answer.
= (150 * 6800)/(150+6800)
= 1020000/6950.
= 146.76258993 answer.
(1)
Ashish said:
9 years ago
Formula of product over sum r = (r1 * r2)/(r1 + r2).
r = (150 * 6800)/(150 + 6800),
r = 146.7ohm.
r = (150 * 6800)/(150 + 6800),
r = 146.7ohm.
(1)
Raushan said:
9 years ago
50*6800/(150+6800) = 1020000/6950 = 146.7626.
(1)
Sweety amuru said:
10 years ago
R = 1/R1 + 1/R2 then R = R1R2/R1+R2.
R = 150*6800/150+6800.
R = 147.76.
R = 150*6800/150+6800.
R = 147.76.
(1)
NILESH R PAWAR said:
1 decade ago
R = (R1*R2) /(R1+R2).
= 150*6800/150+6800.
= 1020000/6950.
Total = 146.76259.
= 150*6800/150+6800.
= 1020000/6950.
Total = 146.76259.
RAVI KUMAR K V said:
1 decade ago
R = R1R2/R1+R2.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
Dharm singh meena said:
1 decade ago
This rule is sum of the parallel form resistance Rp = r1*r2/r1+r2 150*6800/150+6800 = 147.76.
Vijay said:
1 decade ago
r1=150,r2=6800
r1*r2=1020000
r1+r2=6950
(r1*r2)/(r1+r2)=1020000/6950
=146.76
r1*r2=1020000
r1+r2=6950
(r1*r2)/(r1+r2)=1020000/6950
=146.76
Mohammad Shafiq said:
1 decade ago
This is the rule in parallel circuit that the total resistance of parallel circuit is nearly less than from the smallest resistance in parallel circuit so in these answers nearly value is 146.7 and also from formula given above.
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