Electronics - Parallel Circuits - Discussion

2. 

What is the product-over-sum result of 150 and 6800?

[A]. 150
[B]. 146.7
[C]. 0.006
[D]. 6800

Answer: Option B

Explanation:

No answer description available for this question.

Purwa Upadhyay said: (Oct 27, 2010)  
Formula of: product-over-sum r=(r1*r2)/(r1+r2)
r=(150*6800)/(150+6800)
r=146.7ohm

Laran said: (Oct 30, 2010)  
product=150*6800=1020000
sum=150+6800=6950
product-over-sum=1020000/6950=146.7

Thara said: (Sep 7, 2011)  
sum=150+6800
product=150*6800
therefore
product over sum=1020000/6950
=146.7

S. Mohammed Audhil said: (Oct 4, 2011)  
Friends,

Parallel resistance R=(R1*R2)/(R1+R2)
where R1, R2 are the two parallel resistors

Hence,
R = (150*6800)/(150+6800) = 146.7.

Vikas said: (Oct 25, 2011)  
This is law of parallel addition of resistance.

R = r1*r2/r1+r2 = 146.7

Vidyanand Bharti said: (Jan 31, 2012)  
R{EQ)=R1*R2 /R1+R2 =150*6800/150+6800=146.7

Ravikumar said: (May 20, 2012)  
Name suggested product over sum means first product the given values and then sum it now results of both are divided prodect over sum example: two values say R1&R2 the resultant product of sum is R= (R1*R2) / (R1+R2).

Mohammad Shafiq said: (Jul 29, 2012)  
This is the rule in parallel circuit that the total resistance of parallel circuit is nearly less than from the smallest resistance in parallel circuit so in these answers nearly value is 146.7 and also from formula given above.

Vijay said: (Nov 6, 2012)  
r1=150,r2=6800
r1*r2=1020000
r1+r2=6950
(r1*r2)/(r1+r2)=1020000/6950
=146.76

Dharm Singh Meena said: (Aug 7, 2013)  
This rule is sum of the parallel form resistance Rp = r1*r2/r1+r2 150*6800/150+6800 = 147.76.

Ravi Kumar K V said: (Apr 11, 2014)  
R = R1R2/R1+R2.

R1 = 150.
R2 = 6800.

R = 150*6800/150+6800.
R = 147.76.

Nilesh R Pawar said: (Aug 11, 2014)  
R = (R1*R2) /(R1+R2).
= 150*6800/150+6800.
= 1020000/6950.

Total = 146.76259.

Sweety Amuru said: (Jan 27, 2016)  
R = 1/R1 + 1/R2 then R = R1R2/R1+R2.

R = 150*6800/150+6800.

R = 147.76.

Raushan said: (Mar 12, 2016)  
50*6800/(150+6800) = 1020000/6950 = 146.7626.

Ashish said: (Sep 7, 2016)  
Formula of product over sum r = (r1 * r2)/(r1 + r2).
r = (150 * 6800)/(150 + 6800),
r = 146.7ohm.

B.Ramya said: (Apr 8, 2017)  
Product over sum = product/sum = (r1*r2)/(r1+r2).
= (150 * 6800)/(150+6800)
= 1020000/6950.
= 146.76258993 answer.

Jadav said: (Apr 24, 2019)  
product = 6800*150,
Sum = 6800+150,
Ans = product/ sum = 146.7.

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