Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)
2.
What is the product-over-sum result of 150 and 6800?
Discussion:
17 comments Page 2 of 2.
RAVI KUMAR K V said:
1 decade ago
R = R1R2/R1+R2.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
R1 = 150.
R2 = 6800.
R = 150*6800/150+6800.
R = 147.76.
NILESH R PAWAR said:
1 decade ago
R = (R1*R2) /(R1+R2).
= 150*6800/150+6800.
= 1020000/6950.
Total = 146.76259.
= 150*6800/150+6800.
= 1020000/6950.
Total = 146.76259.
Sweety amuru said:
10 years ago
R = 1/R1 + 1/R2 then R = R1R2/R1+R2.
R = 150*6800/150+6800.
R = 147.76.
R = 150*6800/150+6800.
R = 147.76.
(1)
Raushan said:
9 years ago
50*6800/(150+6800) = 1020000/6950 = 146.7626.
(1)
Ashish said:
9 years ago
Formula of product over sum r = (r1 * r2)/(r1 + r2).
r = (150 * 6800)/(150 + 6800),
r = 146.7ohm.
r = (150 * 6800)/(150 + 6800),
r = 146.7ohm.
(1)
B.Ramya said:
8 years ago
Product over sum = product/sum = (r1*r2)/(r1+r2).
= (150 * 6800)/(150+6800)
= 1020000/6950.
= 146.76258993 answer.
= (150 * 6800)/(150+6800)
= 1020000/6950.
= 146.76258993 answer.
(1)
Jadav said:
6 years ago
product = 6800*150,
Sum = 6800+150,
Ans = product/ sum = 146.7.
Sum = 6800+150,
Ans = product/ sum = 146.7.
(2)
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