Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 13)
13.
If a 1 k
and a 2 k resistor are parallel-connected across a 12 V supply, how much current is received by the 2 k resistor?
and a 2 k resistor are parallel-connected across a 12 V supply, how much current is received by the 2 k resistor?Discussion:
28 comments Page 2 of 3.
Javed said:
1 decade ago
Both resistors are in parallel so voltage remains same.
I1 at 2k=V/R i.e. 12/2K=6mA
I1 at 2k=V/R i.e. 12/2K=6mA
JAGGUBAI said:
1 decade ago
V = IR
I = V/R
So V = 12V ,R = 2000 ohms
I = 12/2000 = 0.006 = 6mA
I = V/R
So V = 12V ,R = 2000 ohms
I = 12/2000 = 0.006 = 6mA
Suchitra said:
1 decade ago
Voltage division formula r2=r1*I/r1+r2;r1=r2*I/r1+r2
HARENDRA KUMAR said:
1 decade ago
In parallel circuit voltage remains same.
So, I1=V/R1=12/1=12mA.
I2=V/R1=12/2=6mA. This is right answer.
So for this question option B is true.
So, I1=V/R1=12/1=12mA.
I2=V/R1=12/2=6mA. This is right answer.
So for this question option B is true.
Jaideep said:
1 decade ago
Can we use current divider rule here?
Vedanti said:
1 decade ago
I1 = V/R1 = 12mA,
I2 = V/R2 = 6mA,
These are the currents flowing through individual branches. But if the resistances are connected in parallel.
Total current = 18mA.
So in across 1st resistance 12 mA will get drop so 6 mA will flow through 2nd resistor.
I2 = V/R2 = 6mA,
These are the currents flowing through individual branches. But if the resistances are connected in parallel.
Total current = 18mA.
So in across 1st resistance 12 mA will get drop so 6 mA will flow through 2nd resistor.
Senthil said:
1 decade ago
My simple way to calculate the current flowing through 2kohm resistance is,
If we are exchange 1KOhm resistance by 2 parallel connected 2KOhm resistance, the total circuit will become 3 parallel connected 2KOhm resistances which are having voltage source of 12v.
Total current flowing through the circuit is 18A. So 6mA current will flow through 3 branches of the circuit.
If we are exchange 1KOhm resistance by 2 parallel connected 2KOhm resistance, the total circuit will become 3 parallel connected 2KOhm resistances which are having voltage source of 12v.
Total current flowing through the circuit is 18A. So 6mA current will flow through 3 branches of the circuit.
Prasanna kumar said:
1 decade ago
There is formula for this: i2 = (r1*I/r1+r2).
I = total current.
I = total current.
Suraj said:
1 decade ago
In || circuit the voltage drop is same so v = 12 answer resistance is 2. So effective I = v/R, 12/2 = 6. So answer B.
S.BalaKumar said:
1 decade ago
We know the parallel circuit voltage is same. The voltage across the 2 K ohm resistor is 12 v.
Apply I = V/R. I = 12/2 kohm = 6 ma.
Apply I = V/R. I = 12/2 kohm = 6 ma.
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