Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 27)
27.
If 550 mA of current leaves a node that had 250 mA entering from one branch, how much current would enter from the other?
250 mA
300 mA
550 mA
800 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

M.Dinesh ece NEC (Batch 07-11) said:   1 decade ago
Iout=I1+I2; 550=250+300

Abi said:   1 decade ago
I1-I2=550-250=300

Naren said:   1 decade ago
Explain in words.

Chandrakala said:   1 decade ago
This is kcl.

That s sum of the currents entering the node=sum of the currents leaving the node.

SONI SRIVASTAVA said:   1 decade ago
This is the kirchoff current law
Sum of the currents entering the node=sum of the currents leaving the node

I1=550ma
I2=250mA
I3=?
I1=I2+I3

I3=I1-I2
=550-250=300MA.
I2=250ma

Bibin thomas kerala said:   8 years ago
Thnaks, @Soni Srivastava.

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