Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 27)
27.
If 550 mA of current leaves a node that had 250 mA entering from one branch, how much current would enter from the other?
Discussion:
6 comments Page 1 of 1.
Bibin thomas kerala said:
7 years ago
Thnaks, @Soni Srivastava.
SONI SRIVASTAVA said:
1 decade ago
This is the kirchoff current law
Sum of the currents entering the node=sum of the currents leaving the node
I1=550ma
I2=250mA
I3=?
I1=I2+I3
I3=I1-I2
=550-250=300MA.
I2=250ma
Sum of the currents entering the node=sum of the currents leaving the node
I1=550ma
I2=250mA
I3=?
I1=I2+I3
I3=I1-I2
=550-250=300MA.
I2=250ma
Chandrakala said:
1 decade ago
This is kcl.
That s sum of the currents entering the node=sum of the currents leaving the node.
That s sum of the currents entering the node=sum of the currents leaving the node.
Naren said:
1 decade ago
Explain in words.
Abi said:
1 decade ago
I1-I2=550-250=300
M.Dinesh ece NEC (Batch 07-11) said:
1 decade ago
Iout=I1+I2; 550=250+300
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