Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 37)
37.
What is the total resistance?


Discussion:
6 comments Page 1 of 1.
Anshul said:
1 decade ago
Power as seen on wattmeter = 1.491W
Voltage =48V
As we know P=V^2/R
By this relation we get R=1.545 Kohm
Voltage =48V
As we know P=V^2/R
By this relation we get R=1.545 Kohm
Barun singh said:
1 decade ago
The value of R4 is not give then how you take it 1k.
Madhavi said:
1 decade ago
@ Barun
As per Anshul said,
P=V^2/R
hence R=1.545
As R=(1/R1)+(1/R2)+(1/R3)+R4
(1/R1)+(1/R2)+(1/R3)=0.545K
That's why R4=1K
As per Anshul said,
P=V^2/R
hence R=1.545
As R=(1/R1)+(1/R2)+(1/R3)+R4
(1/R1)+(1/R2)+(1/R3)=0.545K
That's why R4=1K
Jaggubai said:
1 decade ago
In this power is given so R4 value not requried
R=P/V^2
=1494/48*48
=1.54 ohms
R=P/V^2
=1494/48*48
=1.54 ohms
Ranjith said:
10 years ago
P = V^2/R.
R = V^2/P.
= (48*48)/1.491.
= 1.545 kohm.
R = V^2/P.
= (48*48)/1.491.
= 1.545 kohm.
Ajay bhardwaj said:
9 years ago
@Jaggubai.
From where P/V= 1.494 comes.
From where P/V= 1.494 comes.
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