Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 19)
19.
What is the total power of the circuit?
Discussion:
15 comments Page 2 of 2.
JOSEPH said:
10 years ago
Where did you get 11k?
Rajesh said:
9 years ago
In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer
In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer
In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.
B.Ramya said:
8 years ago
Power= Interms of voltage is V^2/R.
R Total is = r1//r2//r3.
= 1k//2k//3k,
= 6/11k.
Therefore The Total power = ((48v * 48v) * 11)/6k,
= 4224/k,
= 4.224Watts,
= 4.2 Watts.
R Total is = r1//r2//r3.
= 1k//2k//3k,
= 6/11k.
Therefore The Total power = ((48v * 48v) * 11)/6k,
= 4224/k,
= 4.224Watts,
= 4.2 Watts.
Shinoj said:
8 years ago
1/Rt=1/R1+1/R2+1/R3.
1/Rt=1/1+1/2+1/3,
1/Rt=1+0.5+0.33,
1/Rt=1.83,
Rt=1/1.83,
Rt=0.546K ohm.
I=V/R.
I=48/.546,
I=88mA.
P=VxI.
P=48x.088A,
P=4.224W.
1/Rt=1/1+1/2+1/3,
1/Rt=1+0.5+0.33,
1/Rt=1.83,
Rt=1/1.83,
Rt=0.546K ohm.
I=V/R.
I=48/.546,
I=88mA.
P=VxI.
P=48x.088A,
P=4.224W.
Mallikarjun said:
7 years ago
How 11k come? Please explain.
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