# Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 19)

19.

What is the total power of the circuit?

Discussion:

15 comments Page 1 of 2.
Mallikarjun said:
6 years ago

How 11k come? Please explain.

(1)

Shinoj said:
7 years ago

1/Rt=1/R1+1/R2+1/R3.

1/Rt=1/1+1/2+1/3,

1/Rt=1+0.5+0.33,

1/Rt=1.83,

Rt=1/1.83,

Rt=0.546K ohm.

I=V/R.

I=48/.546,

I=88mA.

P=VxI.

P=48x.088A,

P=4.224W.

1/Rt=1/1+1/2+1/3,

1/Rt=1+0.5+0.33,

1/Rt=1.83,

Rt=1/1.83,

Rt=0.546K ohm.

I=V/R.

I=48/.546,

I=88mA.

P=VxI.

P=48x.088A,

P=4.224W.

B.Ramya said:
7 years ago

Power= Interms of voltage is V^2/R.

R Total is = r1//r2//r3.

= 1k//2k//3k,

= 6/11k.

Therefore The Total power = ((48v * 48v) * 11)/6k,

= 4224/k,

= 4.224Watts,

= 4.2 Watts.

R Total is = r1//r2//r3.

= 1k//2k//3k,

= 6/11k.

Therefore The Total power = ((48v * 48v) * 11)/6k,

= 4224/k,

= 4.224Watts,

= 4.2 Watts.

Rajesh said:
8 years ago

In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.

So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer

In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.

So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer

In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.

JOSEPH said:
9 years ago

Where did you get 11k?

Alka Sutar said:
9 years ago

Equation of resistance of circuit = R = R1||R2||R3.

R = 6/11K.

POWER = V2/R.

= (48*48)*11/6K.

= 4.224 mA.

R = 6/11K.

POWER = V2/R.

= (48*48)*11/6K.

= 4.224 mA.

SAN said:
1 decade ago

I = V/R THEN TO FIND POWER P = V*I.

I1 = V1/R1 = 48/1000 = 0.048.

I2 = V1/R2 = 48/2000 = 0.024.

I3 = V1/R3 = 48/3000 = 0.016.

TOTAL CURRENT = I1+I2+I3 = 0.048+0.024+0.016 = 0.088.

POWER = V*I = 48*0.088 = 4.224WATTS.

I1 = V1/R1 = 48/1000 = 0.048.

I2 = V1/R2 = 48/2000 = 0.024.

I3 = V1/R3 = 48/3000 = 0.016.

TOTAL CURRENT = I1+I2+I3 = 0.048+0.024+0.016 = 0.088.

POWER = V*I = 48*0.088 = 4.224WATTS.

Rathi said:
1 decade ago

@Ali Umar.

Another way are = R1*R2*R3/(R2*R3 + R1*R3 + R1*R2).

1*2*3/(2*3 + 1*3 + 1*2) = 6/11.

Another way are = R1*R2*R3/(R2*R3 + R1*R3 + R1*R2).

1*2*3/(2*3 + 1*3 + 1*2) = 6/11.

Ali Umar said:
1 decade ago

Can any body give give justification.

In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.

So 1/R = 1/1 + 1/2 + 1/3 = 11/6 ==> are = 6/11 kOhm Answer.

I another way are = R1*R2*R3/ (R1+R2+R3) =1*2*3/ (1+2+3) =1kOhm Answer.

My question is Why my answer is coming different. Please help me.

In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.

So 1/R = 1/1 + 1/2 + 1/3 = 11/6 ==> are = 6/11 kOhm Answer.

I another way are = R1*R2*R3/ (R1+R2+R3) =1*2*3/ (1+2+3) =1kOhm Answer.

My question is Why my answer is coming different. Please help me.

Divya vinoth said:
1 decade ago

Rt=1kohms( by parallel resistance formula)

P=V^2/R

P=48^2/1k

P=4.224W

P=V^2/R

P=48^2/1k

P=4.224W

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