Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 19)
19.
What is the total power of the circuit?
Discussion:
15 comments Page 1 of 2.
B.Ramya said:
8 years ago
Power= Interms of voltage is V^2/R.
R Total is = r1//r2//r3.
= 1k//2k//3k,
= 6/11k.
Therefore The Total power = ((48v * 48v) * 11)/6k,
= 4224/k,
= 4.224Watts,
= 4.2 Watts.
R Total is = r1//r2//r3.
= 1k//2k//3k,
= 6/11k.
Therefore The Total power = ((48v * 48v) * 11)/6k,
= 4224/k,
= 4.224Watts,
= 4.2 Watts.
Ali Umar said:
1 decade ago
Can any body give give justification.
In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 ==> are = 6/11 kOhm Answer.
I another way are = R1*R2*R3/ (R1+R2+R3) =1*2*3/ (1+2+3) =1kOhm Answer.
My question is Why my answer is coming different. Please help me.
In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 ==> are = 6/11 kOhm Answer.
I another way are = R1*R2*R3/ (R1+R2+R3) =1*2*3/ (1+2+3) =1kOhm Answer.
My question is Why my answer is coming different. Please help me.
SAN said:
1 decade ago
I = V/R THEN TO FIND POWER P = V*I.
I1 = V1/R1 = 48/1000 = 0.048.
I2 = V1/R2 = 48/2000 = 0.024.
I3 = V1/R3 = 48/3000 = 0.016.
TOTAL CURRENT = I1+I2+I3 = 0.048+0.024+0.016 = 0.088.
POWER = V*I = 48*0.088 = 4.224WATTS.
I1 = V1/R1 = 48/1000 = 0.048.
I2 = V1/R2 = 48/2000 = 0.024.
I3 = V1/R3 = 48/3000 = 0.016.
TOTAL CURRENT = I1+I2+I3 = 0.048+0.024+0.016 = 0.088.
POWER = V*I = 48*0.088 = 4.224WATTS.
Bharti S.K. said:
1 decade ago
In the given Ckt. Eq. resistance of the circuit Req. = R1||R2||R3
1/R = 1/1K+1/2K+1/3K = 11/6 K
So R = 6/11 K
Hence Total Power P = V.V/R = (48*48)11/6K
= 4.224 mA
1/R = 1/1K+1/2K+1/3K = 11/6 K
So R = 6/11 K
Hence Total Power P = V.V/R = (48*48)11/6K
= 4.224 mA
Rajesh said:
9 years ago
In Parallel connection Formula is 1/R = 1/R1 + 1/R2 + 1/R3.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer
In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.
So 1/R = 1/1 + 1/2 + 1/3 = 11/6 => 6/11 kOhm Answer
In another way are = R1*R2*R3 / (R1+R2+R3) = 1*2*3 / (1+2+3) = 1kOhm Answer.
Snehashis said:
1 decade ago
In the given circuit eq resistance=R1//R2//R3 = 6/11k
now total current flowing in the circuit isi=v/r=48/(6/11)*1000
=0.088A
Now power loss p=i*iR=4.2w
now total current flowing in the circuit isi=v/r=48/(6/11)*1000
=0.088A
Now power loss p=i*iR=4.2w
Shinoj said:
8 years ago
1/Rt=1/R1+1/R2+1/R3.
1/Rt=1/1+1/2+1/3,
1/Rt=1+0.5+0.33,
1/Rt=1.83,
Rt=1/1.83,
Rt=0.546K ohm.
I=V/R.
I=48/.546,
I=88mA.
P=VxI.
P=48x.088A,
P=4.224W.
1/Rt=1/1+1/2+1/3,
1/Rt=1+0.5+0.33,
1/Rt=1.83,
Rt=1/1.83,
Rt=0.546K ohm.
I=V/R.
I=48/.546,
I=88mA.
P=VxI.
P=48x.088A,
P=4.224W.
Himanshu Verma said:
1 decade ago
Equivalent resistance of the circuit R = R1||R2||R3
R = 1K||2K||3K = 6/11 K
Power P = V2/R = (48*18*11)/6K = 4.224 mA
R = 1K||2K||3K = 6/11 K
Power P = V2/R = (48*18*11)/6K = 4.224 mA
Nehha said:
1 decade ago
The resistances are connecting in parallel. so
1/R=1/1+1/2+1/3=11/6
Or R=6/11
Power=V.V/R=48.48.11/6
P=4.22w
1/R=1/1+1/2+1/3=11/6
Or R=6/11
Power=V.V/R=48.48.11/6
P=4.22w
Alka Sutar said:
1 decade ago
Equation of resistance of circuit = R = R1||R2||R3.
R = 6/11K.
POWER = V2/R.
= (48*48)*11/6K.
= 4.224 mA.
R = 6/11K.
POWER = V2/R.
= (48*48)*11/6K.
= 4.224 mA.
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