Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 23)
23.
What is the total resistance?
7 k
1 k
706
353
Discussion:
20 comments Page 1 of 2.
Hirenkumar said:
1 decade ago
It is very simple ,
If we calulate like this,
Here,
R1=1k.
R2=2k.
R3=3k.
R4=1k.
If we do R1||R4 then simply 1k||1k=500 Ohms.
So final answer should be less than 500 ohms as there are R2 and R3 are there.
And in option there is only one option which is less than 500 Ohms.
So 353 is the answer.
If we calulate like this,
Here,
R1=1k.
R2=2k.
R3=3k.
R4=1k.
If we do R1||R4 then simply 1k||1k=500 Ohms.
So final answer should be less than 500 ohms as there are R2 and R3 are there.
And in option there is only one option which is less than 500 Ohms.
So 353 is the answer.
(1)
Ragaviganesan said:
1 decade ago
Hello Friends.
There are three resistance values...say R1, R2, R3, R4.
First calculate R1||R2 = 2/3 = r1 then, r1||R3 = 6/11 = r2 then, r2||R4 = 0.3529K = 353 ohm.
Finally R1||R2||R3||R4 = 353 ohm.
There are three resistance values...say R1, R2, R3, R4.
First calculate R1||R2 = 2/3 = r1 then, r1||R3 = 6/11 = r2 then, r2||R4 = 0.3529K = 353 ohm.
Finally R1||R2||R3||R4 = 353 ohm.
Ali Umar said:
1 decade ago
1/Requ = 1/R1 + 1/R2 + 1/R3 = 1/1 + 1/2 + 1/3 + 1/1 = 17/6 kohm.
Requ = 6/17 Kohm.
Now convert 6/17 kohm into ohm so multiply with 1000(1kohm=1000ohm).
So 6/17*1000 = 352.94.
Requ = 6/17 Kohm.
Now convert 6/17 kohm into ohm so multiply with 1000(1kohm=1000ohm).
So 6/17*1000 = 352.94.
Krushna waghmare said:
1 decade ago
RT = 1/R1+1/R2+1/R3+1/R4........1/RN formula 1/1000, 1/2000, 1/3000, 1/1000.
RT = 5+2.5+1.66+5/5000 Lasavi.
= 14.16/5000 Moho.
= 5000/14.16 ohm.
Answer = 353 ohms.
RT = 5+2.5+1.66+5/5000 Lasavi.
= 14.16/5000 Moho.
= 5000/14.16 ohm.
Answer = 353 ohms.
Anuja said:
5 years ago
I don't understand total resistance in parallel (1/R1)+( 1/R2)+(1/R3)+(1/R4) so please give me answer and explain in simple words?
Anuja said:
5 years ago
I don't know total resistance in parallel (1/R1)+(1/R2)+(1/R3)+(1/R4).
So, please give me an answer and explain in simple.
So, please give me an answer and explain in simple.
Abhi said:
9 years ago
Try to send current through one of the points from open circuit side and try to reduce it by parallel rule.
Ponman Peter said:
8 years ago
I'm not getting for the fact that only R2 is given and we're required to calculate total resistance.
Pradeep said:
1 decade ago
How can you calculate for only 2 resistance when they have asked us total find total resistance ?
Aastha said:
1 decade ago
Sorry @Ragavignesham I am unable to understand. Can you please explain in more words?
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