Discussion :: Parallel Circuits - General Questions (Q.No.23)
What is the total resistance?
Answer: Option D
No answer description available for this question.
|Pradnya said: (Dec 7, 2010)|
|Try this formula.
Req = (R1*R2)/R1+R2.
|Nithesh said: (Jan 7, 2011)|
|1/Req = (1/R1)+(1/R2)+(1/R3)+(1/R4)|
|Pradeep said: (Feb 3, 2011)|
|How can you calculate for only 2 resistance when they have asked us total find total resistance ?|
|Jeetu said: (Feb 14, 2011)|
|Hi, pradeep. You have to go forward by using that formula. Its a sample formula.|
|Naseem Ul Aziz said: (May 6, 2011)|
|Pavan said: (May 22, 2011)|
|Nice explanation naseem.|
|Suvu said: (Oct 5, 2011)|
|Shiju.M.P said: (Jan 19, 2012)|
|Total Resistant in parallel= Rt=r1*r2*r3/r1+r2+r3|
|Prasanna said: (Aug 19, 2012)|
|Shiju.M.P this formula does not work here|
|Harendra Kumar said: (Sep 16, 2012)|
|Naceem your explation is not understandable.|
|Ali Umar said: (Mar 25, 2013)|
|1/Requ = 1/R1 + 1/R2 + 1/R3 = 1/1 + 1/2 + 1/3 + 1/1 = 17/6 kohm.
Requ = 6/17 Kohm.
Now convert 6/17 kohm into ohm so multiply with 1000(1kohm=1000ohm).
So 6/17*1000 = 352.94.
|Ragaviganesan said: (Sep 9, 2013)|
There are three resistance values...say R1, R2, R3, R4.
First calculate R1||R2 = 2/3 = r1 then, r1||R3 = 6/11 = r2 then, r2||R4 = 0.3529K = 353 ohm.
Finally R1||R2||R3||R4 = 353 ohm.
|Hirenkumar said: (Jan 16, 2014)|
|It is very simple ,
If we calulate like this,
If we do R1||R4 then simply 1k||1k=500 Ohms.
So final answer should be less than 500 ohms as there are R2 and R3 are there.
And in option there is only one option which is less than 500 Ohms.
So 353 is the answer.
|Aastha said: (Oct 25, 2014)|
|Sorry @Ragavignesham I am unable to understand. Can you please explain in more words?|
|Krushna Waghmare said: (Jan 18, 2015)|
|RT = 1/R1+1/R2+1/R3+1/R4........1/RN formula 1/1000, 1/2000, 1/3000, 1/1000.
RT = 5+2.5+1.66+5/5000 Lasavi.
= 14.16/5000 Moho.
= 5000/14.16 ohm.
Answer = 353 ohms.
|Abhi said: (Jun 25, 2016)|
|Try to send current through one of the points from open circuit side and try to reduce it by parallel rule.|
|Njmadeen said: (Oct 4, 2017)|
|Ponman Peter said: (Jan 11, 2018)|
|I'm not getting for the fact that only R2 is given and we're required to calculate total resistance.|
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