Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 15)
15.
The current through R1 will be:


Discussion:
17 comments Page 1 of 2.
Seshendra said:
1 decade ago
Voltage across parallel resistors are same.
So voltage across R1 is 48v,
We Know i=v/r.
=48mA.
So voltage across R1 is 48v,
We Know i=v/r.
=48mA.
Niraj kumar said:
1 decade ago
Total resistance Rt=(1*2*3)/(1+2+3)=1
I=V/Rt
I=48/1*10^3=48mA
I=V/Rt
I=48/1*10^3=48mA
ROOPA.R said:
1 decade ago
0.088-0.040=0.048or 48mA
(I1=I2+I3)
SO I3=I1-I2
(I1=I2+I3)
SO I3=I1-I2
Vasu said:
1 decade ago
In the answer given by Nirak kumar , Req= 1
but, its wrong. The correct formula in case of 3 r's in || is Req=R1R2R3/(R1R2+R2R3+R3R1).
So here Req will become 6/11.
but, its wrong. The correct formula in case of 3 r's in || is Req=R1R2R3/(R1R2+R2R3+R3R1).
So here Req will become 6/11.
Chaitanya said:
1 decade ago
Vasu is correct
Ragi G R said:
1 decade ago
By simple logic we can find it. The current in the previous branch is 0.088. This current get split into two branches. One of them is 0.040.
So the current in the required branch is 0.088-0.040=48mA
So the current in the required branch is 0.088-0.040=48mA
Yamini said:
1 decade ago
The current in the first loop is 88mA,in the second loop is 40mA,
So the current across r1 is the difference between the 2 currents,that is 88m-40m=48mA
So the current across r1 is the difference between the 2 currents,that is 88m-40m=48mA
Dipika said:
1 decade ago
@Niraj is correct answer becoz this three resistsnce are parellel so formula is r1*r2*r3/r1+r2+r3... so total resi r..
& then after ohms law apply...
& then after ohms law apply...
Harika said:
1 decade ago
@according to vasu as req=6/11
I=V/Req =48*(11/6)=88mA
I=V/Req =48*(11/6)=88mA
Shiva said:
1 decade ago
I = 0.088.
I1 = ?
I2 = 0.040.
Since I = I1+I2 (Kirchhoff current law).
I1 = I-I2 = 0.088 - 0.040 = 0.048 = 48 x 10^-3 = 48mA.
I1 = ?
I2 = 0.040.
Since I = I1+I2 (Kirchhoff current law).
I1 = I-I2 = 0.088 - 0.040 = 0.048 = 48 x 10^-3 = 48mA.
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