Electronics - Parallel Circuits - Discussion

Considering the ohms law p=v^2/R so, if are is low power loss is more.

The resistors are in parallel & in parallel voltage is same but in parallel current divides, current follows the low resistive path, so high pwr loss occurs in small resistance.

In parallel voltage constant dats by we take p=v^2/r...if we take p=i^28r...p may vary with variation of "i" bt in p=v^2/r.....p varies with variation of r.

As the resistors are connected in parallel, the voltages are same. According to P=V^2/R smaller the resistance greater the power loss.

The total source voltage equal to the voltage across elements, according to this V=IR (voltage drop depends on current and resistance value only). The current flow value depends on voltage source are connected to that circuits and resistance value, so that power loss mainly depends on the resistance and voltage value only. Due to this P=VI=V2/R (power in inversely proportional to the resistance). The maximum power loss will occur if low resistance value.

Since the tendency of current is to chose least resistance path and p=i^2r then the current inside lowest resistance will higher so the power is also higher.

What is the difference between power loss and power?

More current will pass through the lowest resistor and we know that p = i^2*r.

Power is inversely proportional to resistance. So less value of resistance has great power loss.

Please explain power and what's the difference between power and voltage here ?