Electronics - Parallel Circuits - Discussion

The right answer should be the smallest resistance since from the formula P = V^2/R if R is small Power is greater.

In formula P = I^2 *R if R is small I would be large and P would also be the largest. In the formula P= I*V since R is small then I is large and since it is parallel so V is constant therefore P would still be the largest.

Ex. Given 3 components in parallel with 60 V source.

R1 = 20 ohms, V1 = 60V, I = 3A, P=IV = 180 W, P=V^2/R = 180W, P=I^2 * R= 180W.
R2 = 40 ohms, V2 = 60V, I = 1.5A, P=IV = 90W, P=V^2/R = 90W, P=I^2 * R= 180W.
R3 = 60 ohms, V3 = 60V, I = 1 A, P=IV = 60W, P=V^2/R = 60W, P=I^2 * R= 180W.

In conclusion, the one with the smallest resistance will always has the largest power.

The total source voltage equal to the voltage across elements, according to this V=IR (voltage drop depends on current and resistance value only). The current flow value depends on voltage source are connected to that circuits and resistance value, so that power loss mainly depends on the resistance and voltage value only. Due to this P=VI=V2/R (power in inversely proportional to the resistance). The maximum power loss will occur if low resistance value.

@All.

As the question referred to the greatest power loss in which resistance, not the greatest power consumed.

Let put in a nutshell power loss proportional to resistor value, consider resistor as a load and load drop occurs in the resistor and at the same time loss component is there in resistor which is exhibited in terms of heat. If resistor value is high heat will be high and of course, loss is high.

Let,

R1= 2ohm.
R2= 4ohm.
R3=6ohm and Vs=12 V.
and according to the question all the resistors connected in parallel.
P1=V^2/R1 =12*12/2 = 72 W.
P2 = V^2/R2 = 12*12/4 =36 W.
P3 = V^2/R3 = 12*12/6 = 24 W.

Now, you can see small resistance have greater power loss than other
Note:- All the values are an assumption you can check by posting of different values or different methods to remember.

Current always choose low resistance path. So the current flow through the resister is high. And the voltage across all resisters is equal when they connected in parallel know apply p=vi.

So here i is high when its having small resistance value so therefore p also high through the resister which is having smaller value.

The greatest resistance has the highest power loss.
Because Voltage will be same for all resistance.

And the highest current flow from the lowest value of resistance,
Because I = V/R.
So now P = VI.

So the lowest value resistance has the max. power and so on power loss will be minimum.

So option B is right.

When three resistances are connected parallel with same battery(cell)of voltage v . current divides & flows through parallel combination of resistances. max. current flows though the resistor of smaller value

as p=vi here i is large for smaller value of resistor.

p=vi,
v=ir,
i=v/r,
so
p= v2/r

In problem the resistors are in parallel. The voltage across parellell resistors are same. So V is constant.
Now Power is inversely proportional to resistance. Less resistance value resistor have the gretest power loss....

In the equation P=(I^2)R ...........I is not constant so we cant consider it.

Hence P=V2/R is correct as in this case V is constant as parallel resistance has same voltage.

However if it would have been series circuit then your answer will be right.

In simple Short circuit haven't any load(That mean havn't parallel
Resistors )(In short circuit power loss is occur).So small resistance is almost like to short circuit..AS A RESULT SMALL RESISTANCE IS FOR HIGH POWER LOSS.