Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 1)
1.
When parallel resistors are of three different values, which has the greatest power loss?
Discussion:
32 comments Page 4 of 4.
Jadav said:
6 years ago
Because W=I*I*R.
So small resistance have high current and power is square of the current.
So, Ans is the smallest resistance.
So small resistance have high current and power is square of the current.
So, Ans is the smallest resistance.
(1)
Bruhmagupta said:
4 years ago
The right answer should be the smallest resistance since from the formula P = V^2/R if R is small Power is greater.
In formula P = I^2 *R if R is small I would be large and P would also be the largest. In the formula P= I*V since R is small then I is large and since it is parallel so V is constant therefore P would still be the largest.
Ex. Given 3 components in parallel with 60 V source.
R1 = 20 ohms, V1 = 60V, I = 3A, P=IV = 180 W, P=V^2/R = 180W, P=I^2 * R= 180W.
R2 = 40 ohms, V2 = 60V, I = 1.5A, P=IV = 90W, P=V^2/R = 90W, P=I^2 * R= 180W.
R3 = 60 ohms, V3 = 60V, I = 1 A, P=IV = 60W, P=V^2/R = 60W, P=I^2 * R= 180W.
In conclusion, the one with the smallest resistance will always has the largest power.
In formula P = I^2 *R if R is small I would be large and P would also be the largest. In the formula P= I*V since R is small then I is large and since it is parallel so V is constant therefore P would still be the largest.
Ex. Given 3 components in parallel with 60 V source.
R1 = 20 ohms, V1 = 60V, I = 3A, P=IV = 180 W, P=V^2/R = 180W, P=I^2 * R= 180W.
R2 = 40 ohms, V2 = 60V, I = 1.5A, P=IV = 90W, P=V^2/R = 90W, P=I^2 * R= 180W.
R3 = 60 ohms, V3 = 60V, I = 1 A, P=IV = 60W, P=V^2/R = 60W, P=I^2 * R= 180W.
In conclusion, the one with the smallest resistance will always has the largest power.
(1)
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