Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 12)
12.
In the given circuit, Channel 1 of the stereo amplifier outputs 12 V to the speakers. How much total power is the amplifier delivering to the speakers?
Discussion:
12 comments Page 1 of 2.
Krunal said:
9 years ago
p = v * i
v = 12,
i = ?
R = r1 * r2/r1 + r2.
= 8 * 8/8 + 8,
= 64/16,
R = 4.
v = ir,
i = v/r,
= 12/4,
i = 3.
p = vi.
p = 12 * 3,
p = 36.
v = 12,
i = ?
R = r1 * r2/r1 + r2.
= 8 * 8/8 + 8,
= 64/16,
R = 4.
v = ir,
i = v/r,
= 12/4,
i = 3.
p = vi.
p = 12 * 3,
p = 36.
(3)
Pre said:
9 years ago
p = i^2 * r.
r = r1 * r2/r1 + r2.
=> 8 * 8/8 + 8,
=> 64/16,
=> 4,
r = 4.
Don't we know I?
So that;
i = (v/r).
p = (v/r)^2 * r,
p = ((12/4)^2) * 4,
p = (3^2) * 4,
p = 9 * 4,
p = 36.
Then the answer is 36- (c).
r = r1 * r2/r1 + r2.
=> 8 * 8/8 + 8,
=> 64/16,
=> 4,
r = 4.
Don't we know I?
So that;
i = (v/r).
p = (v/r)^2 * r,
p = ((12/4)^2) * 4,
p = (3^2) * 4,
p = 9 * 4,
p = 36.
Then the answer is 36- (c).
(1)
Harshvardhan nirmal said:
1 decade ago
p=vi, but v=ir.
Therefore. p=i^2r.
r=8*8/8+8=4.
i=v/r v/r=12/4=3.
p=v*(v/r).
p=12*3=36W.
p=36W.
Therefore. p=i^2r.
r=8*8/8+8=4.
i=v/r v/r=12/4=3.
p=v*(v/r).
p=12*3=36W.
p=36W.
Roja said:
1 decade ago
p = v*i.
v = 12v.
i = i1+i2.
i1 = v/r1 = 12/8 = 3/2MA.
i2 = v/r2 = 12/8 = 3/2MA.
i = 3/2+3/2 = 3MA.
p = v*i = 12*3 = 36W.
v = 12v.
i = i1+i2.
i1 = v/r1 = 12/8 = 3/2MA.
i2 = v/r2 = 12/8 = 3/2MA.
i = 3/2+3/2 = 3MA.
p = v*i = 12*3 = 36W.
ASIF VELLORE said:
1 decade ago
Power formula is 3 type:
1) p=i^2*r
2) p=v^2/r
3) p=v*i
Take a 2 formula for this question p=V^2/R.
FOR 1ST SPEAKER P=144/8 =18W.
FOR 2ND SPEAKER P=144/8 =18W.
TOTAL POWER OF SPEAKER IS = 36W.
1) p=i^2*r
2) p=v^2/r
3) p=v*i
Take a 2 formula for this question p=V^2/R.
FOR 1ST SPEAKER P=144/8 =18W.
FOR 2ND SPEAKER P=144/8 =18W.
TOTAL POWER OF SPEAKER IS = 36W.
Shaikh said:
1 decade ago
w = v2/R.
v =12.
Rt = (r1*r2)/(r1+r2) = 4 ohm.
w = 144/4.
= 36.
v =12.
Rt = (r1*r2)/(r1+r2) = 4 ohm.
w = 144/4.
= 36.
Saurabh kumar said:
1 decade ago
With reference of product over sum.
X1X2/X1+X2.
R1=8.
R2=8.
So then,
R=R1R2/R1+R2.
8*8/8+8=64/16=4ohm.
Given voltage=12v.
Then,
I=12/4.
=3A.
So that,
P = VI.
P = 12*3 = 36W Answer.
X1X2/X1+X2.
R1=8.
R2=8.
So then,
R=R1R2/R1+R2.
8*8/8+8=64/16=4ohm.
Given voltage=12v.
Then,
I=12/4.
=3A.
So that,
P = VI.
P = 12*3 = 36W Answer.
Dilip said:
1 decade ago
First find current,
I=V/R
where R=R1*R2/R1+R2
i.e., 8*8/8+8=4ohm
I=12/4=3A
then,
P=VI
P=12*3=36 watt.
I=V/R
where R=R1*R2/R1+R2
i.e., 8*8/8+8=4ohm
I=12/4=3A
then,
P=VI
P=12*3=36 watt.
Ankit V said:
1 decade ago
In given circuit two resistors are in parallel so effective resistance is 4 ohm and we know P=V*V/R.
So after calculate P= 36 W
So after calculate P= 36 W
Ilavarasan said:
1 decade ago
p=v*i
v=12,
i=?
R=r1*r2/r1+r2
=8*8/8+8
=64/16
R=4
v=ir
i=v/r
=12/4
i=3
p=vi
p=12*3
p=36
v=12,
i=?
R=r1*r2/r1+r2
=8*8/8+8
=64/16
R=4
v=ir
i=v/r
=12/4
i=3
p=vi
p=12*3
p=36
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