Electronics - Operational Amplifiers - Discussion

Discussion Forum : Operational Amplifiers - General Questions (Q.No. 27)
27.
What is the output waveform of the circuit?

sine wave
square wave
sawtooth wave
triangle wave
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.

Darshit said:   1 decade ago
Circuit is in open loop configuration hence output is in saturation means +Vsat and -Vsat which gives square wave.
(2)

Nitin said:   1 decade ago
How is it so?

Umesh saini said:   1 decade ago
Op amp has open loop gain of 2*10^5

Output=2*10^5(10^-3)=200v

This is not possible to have voltage of 200v

When output voltage exceeds vcc(supply voltage=15v)
the opamp saturates and output is square wave.

Anil kumar said:   1 decade ago
In open loop configuration ther is no concept of virtual ground and hence when ever the voltage at the non inverting terminal is greater than inverting terminal the out put is at +vsat and vice versa.

ASHOK KUMAR.R said:   1 decade ago
Here the op amp acts as a comparator because the inverting terminal is grounded. Nothing but the reference voltage at inverting terminal is 0 Volts.

Now it compares non inverting with inverting terminal, so it gives the respective supply voltage whether it is +ve or -ve.

Sidharthan P V said:   8 years ago
There is not negative feed back applied. The open loop gain of the opamp is of the order of 10^5. Then the output would be vin x 10^5 = 10^5 mV = 100 V.

Since the value of Vcc is +/- 15 V, the output will be clipped at I and - saturations. Therefore the output will be square wave.

Rajashekar balya said:   8 years ago
It is a Comparator so if input is sinusoidal then ouput is sqaure wave.

Abinaya said:   1 year ago
The answer is square wave.

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