Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 3)
3.
Convert the binary number 1011010 to hexadecimal.
Discussion:
13 comments Page 1 of 2.
Neethy N said:
1 decade ago
Group 4 bits each from last. It corresponds to 10 that is 'A' in hexadecimal and next four corresponds to '5'
Rupa said:
1 decade ago
How it would be 5A if we convert that into decimal we get 91 and then divide that 91 with 16 then we will get 5 and reminder 11.
So in binary 11 means B.
So the answer may be 5B.
So in binary 11 means B.
So the answer may be 5B.
Kranthi said:
1 decade ago
0101 1010 for converting binary to hexa
5 10 (for 10 value A )
5A
5 10 (for 10 value A )
5A
Csg said:
1 decade ago
0101 1010 for converting binary to hexa.
5 10 (for 10 value A ).
5A.
5 10 (for 10 value A ).
5A.
S kumar said:
1 decade ago
Converting binary to decimal.
2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0=64+0+16+8+0+2+0=90 and so on..converting (90)decimal to hexadecimal.
(16)^1*5+(16)^0*10=510. But in hexadecimal A is the code for digit 10. So answer would be 5A.
2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0=64+0+16+8+0+2+0=90 and so on..converting (90)decimal to hexadecimal.
(16)^1*5+(16)^0*10=510. But in hexadecimal A is the code for digit 10. So answer would be 5A.
(1)
Ashish singh said:
1 decade ago
From last RHS group into four then it becomes 5A.
Asad Mehmood said:
1 decade ago
(1011010) = ?
= 2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0.
= 64+0+16+8+0+2.
= 90.
Now this 90 convert into hexadecimal.
= 16/90_5-10.
= 5A.
A represent 10.
= 2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0.
= 64+0+16+8+0+2.
= 90.
Now this 90 convert into hexadecimal.
= 16/90_5-10.
= 5A.
A represent 10.
Vimal sharma said:
10 years ago
(1011010) = ?
0 1 0 1 1 0 1 0.
1st four digit 0 1 0 1.
= 0*2^3+1*2^2+0*2^1+1*2^0 = 0+4+0+1.
= 5 Answer.
Last four digit 1 0 1 0.
= 1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+1.
= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).
= 11 = B answer.
= 5+B.
= 5B answer.
0 1 0 1 1 0 1 0.
1st four digit 0 1 0 1.
= 0*2^3+1*2^2+0*2^1+1*2^0 = 0+4+0+1.
= 5 Answer.
Last four digit 1 0 1 0.
= 1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+1.
= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).
= 11 = B answer.
= 5+B.
= 5B answer.
Madhuri said:
9 years ago
Last four digit 1 0 1 0.
= 1*2^3 + 0*2^2 + 1*2^1 + 0*2^0 = 8+0+2+1.
= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).
= 11 = B answer.
In the above (0*2^0) is taken as 1 so you got B.
The correct is 8+0+2+0 = 10 = A.
= 1*2^3 + 0*2^2 + 1*2^1 + 0*2^0 = 8+0+2+1.
= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).
= 11 = B answer.
In the above (0*2^0) is taken as 1 so you got B.
The correct is 8+0+2+0 = 10 = A.
Prabir dhara said:
8 years ago
For them who do not know it, 0*2^0=0,(not 1).
So for last four digit 1010 = 10 means (A)[1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+0=10, We know for hexadecimal numbering system is 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,].
So for last four digit 1010 = 10 means (A)[1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+0=10, We know for hexadecimal numbering system is 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,].
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