# Electronics - Number Systems and Codes - Discussion

Discussion Forum : Number Systems and Codes - General Questions (Q.No. 3)

3.

Convert the binary number 1011010 to hexadecimal.

Discussion:

13 comments Page 1 of 2.
Susheela said:
4 years ago

Given (1011010) to the base 10.

Let's divide this binary number into four digits from last. i.e; 0101 1010

as there are only 7 numbers in the given binary form we are adding 0 in front just to make it even.

We have a rule called 8421. according to that;

The binary number 0101= 5 (4+1).

The binary number 1010=10 (8+2).

Then we get the hexadecimal number as 510 = 5A.

Answer= 5A.

Let's divide this binary number into four digits from last. i.e; 0101 1010

as there are only 7 numbers in the given binary form we are adding 0 in front just to make it even.

We have a rule called 8421. according to that;

The binary number 0101= 5 (4+1).

The binary number 1010=10 (8+2).

Then we get the hexadecimal number as 510 = 5A.

Answer= 5A.

Steffen Rohit said:
6 years ago

5A is the correct answer. I agree with the given answer.

Srikar said:
6 years ago

Given binary number is 1011010.

0101 ----- 1010

5 ----- 10 it can be represented as A.

5 ----- A.

So, the answer is 5A.

0101 ----- 1010

5 ----- 10 it can be represented as A.

5 ----- A.

So, the answer is 5A.

Prabir dhara said:
7 years ago

For them who do not know it, 0*2^0=0,(not 1).

So for last four digit 1010 = 10 means (A)[1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+0=10, We know for hexadecimal numbering system is 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,].

So for last four digit 1010 = 10 means (A)[1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+0=10, We know for hexadecimal numbering system is 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,].

Madhuri said:
8 years ago

Last four digit 1 0 1 0.

= 1*2^3 + 0*2^2 + 1*2^1 + 0*2^0 = 8+0+2+1.

= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).

= 11 = B answer.

In the above (0*2^0) is taken as 1 so you got B.

The correct is 8+0+2+0 = 10 = A.

= 1*2^3 + 0*2^2 + 1*2^1 + 0*2^0 = 8+0+2+1.

= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).

= 11 = B answer.

In the above (0*2^0) is taken as 1 so you got B.

The correct is 8+0+2+0 = 10 = A.

Vimal sharma said:
9 years ago

(1011010) = ?

0 1 0 1 1 0 1 0.

1st four digit 0 1 0 1.

= 0*2^3+1*2^2+0*2^1+1*2^0 = 0+4+0+1.

= 5 Answer.

Last four digit 1 0 1 0.

= 1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+1.

= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).

= 11 = B answer.

= 5+B.

= 5B answer.

0 1 0 1 1 0 1 0.

1st four digit 0 1 0 1.

= 0*2^3+1*2^2+0*2^1+1*2^0 = 0+4+0+1.

= 5 Answer.

Last four digit 1 0 1 0.

= 1*2^3+0*2^2+1*2^1+0*2^0 = 8+0+2+1.

= 11 mtlb ex-0 1 2 3 4 5 6 7 8 9 (B).

= 11 = B answer.

= 5+B.

= 5B answer.

Asad Mehmood said:
1 decade ago

(1011010) = ?

= 2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0.

= 64+0+16+8+0+2.

= 90.

Now this 90 convert into hexadecimal.

= 16/90_5-10.

= 5A.

A represent 10.

= 2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0.

= 64+0+16+8+0+2.

= 90.

Now this 90 convert into hexadecimal.

= 16/90_5-10.

= 5A.

A represent 10.

Ashish singh said:
1 decade ago

From last RHS group into four then it becomes 5A.

S kumar said:
1 decade ago

Converting binary to decimal.

2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0=64+0+16+8+0+2+0=90 and so on..converting (90)decimal to hexadecimal.

(16)^1*5+(16)^0*10=510. But in hexadecimal A is the code for digit 10. So answer would be 5A.

2^6*1+2^5*0+2^4*1+2^3*1+2^2*0+2^1*1+2^0*0=64+0+16+8+0+2+0=90 and so on..converting (90)decimal to hexadecimal.

(16)^1*5+(16)^0*10=510. But in hexadecimal A is the code for digit 10. So answer would be 5A.

Csg said:
1 decade ago

0101 1010 for converting binary to hexa.

5 10 (for 10 value A ).

5A.

5 10 (for 10 value A ).

5A.

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