Electronics - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 13)
13.
What is the reluctance of a material that has a length of 0.045 m, a cross-sectional area of 0.015 m2, and a permeability of 2500 µWb/At·m?
Discussion:
7 comments Page 1 of 1.
Meena said:
1 decade ago
Reluctance=length/ (permeability*cross sectional area).
Romnic said:
1 decade ago
But my lecturer say that
S=L/relative permeability*permeability of the medium*cross sectional area.
I think that your answer should be wrong. Isn't? explain me.
S=L/relative permeability*permeability of the medium*cross sectional area.
I think that your answer should be wrong. Isn't? explain me.
Ammad Hafeez said:
1 decade ago
Reluctance(R) = Length(l)/Permeability(µ)*Area(A).
R = 0.045/2500x10^-6 * 0.015
R = 1200.
R = 0.045/2500x10^-6 * 0.015
R = 1200.
KALY BEBE said:
9 years ago
RELUCTANCE = LENGTH/PERMEABILITY * AREA.
Rendl said:
8 years ago
It should be length/permeability * area * absolute permeability.
Syam said:
7 years ago
Thanks for explaining.
(1)
KUBER said:
3 years ago
Opt B(0.27At/Wb) is the right answer.
(1)
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