# Electronics - Magnetism and Electromagnetism - Discussion

### Discussion :: Magnetism and Electromagnetism - General Questions (Q.No.13)

13.

What is the reluctance of a material that has a length of 0.045 m, a cross-sectional area of 0.015 m2, and a permeability of 2500 µWb/At·m?

 [A]. 833.33 µAt/Wb [B]. 0.27 At/Wb [C]. 1200 At/Wb [D]. More information is needed in order to find the reluctance.

Explanation:

No answer description available for this question.

 Meena said: (Mar 5, 2011) Reluctance=length/ (permeability*cross sectional area).

 Romnic said: (Nov 18, 2011) But my lecturer say that S=L/relative permeability*permeability of the medium*cross sectional area. I think that your answer should be wrong. Isn't? explain me.

 Ammad Hafeez said: (Nov 8, 2014) Reluctance(R) = Length(l)/Permeability(µ)*Area(A). R = 0.045/2500x10^-6 * 0.015 R = 1200.

 Kaly Bebe said: (Oct 9, 2016) RELUCTANCE = LENGTH/PERMEABILITY * AREA.

 Rendl said: (May 27, 2017) It should be length/permeability * area * absolute permeability.

 Syam said: (Jan 28, 2019) Thanks for explaining.