Electronics - Magnetism and Electromagnetism - Discussion

13. 

What is the reluctance of a material that has a length of 0.045 m, a cross-sectional area of 0.015 m2, and a permeability of 2500 µWb/At·m?

[A]. 833.33 µAt/Wb
[B]. 0.27 At/Wb
[C]. 1200 At/Wb
[D]. More information is needed in order to find the reluctance.

Answer: Option C

Explanation:

No answer description available for this question.

Meena said: (Mar 5, 2011)  
Reluctance=length/ (permeability*cross sectional area).

Romnic said: (Nov 18, 2011)  
But my lecturer say that

S=L/relative permeability*permeability of the medium*cross sectional area.

I think that your answer should be wrong. Isn't? explain me.

Ammad Hafeez said: (Nov 8, 2014)  
Reluctance(R) = Length(l)/Permeability(µ)*Area(A).

R = 0.045/2500x10^-6 * 0.015

R = 1200.

Kaly Bebe said: (Oct 9, 2016)  
RELUCTANCE = LENGTH/PERMEABILITY * AREA.

Rendl said: (May 27, 2017)  
It should be length/permeability * area * absolute permeability.

Syam said: (Jan 28, 2019)  
Thanks for explaining.

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