Electronics - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 3)
3.
What is the flux density of a magnetic field whose flux is 3000 µWb and cross-sectional area is 0.25 m2?
12,000 
T
T83,330 T
0 T
More information is needed in order to find flux density.
Discussion:
16 comments Page 1 of 2.
Meena said:
1 decade ago
B=u*H
H=B/u
H=3000/0.25
H=12000uT
H=B/u
H=3000/0.25
H=12000uT
Sonal said:
1 decade ago
fi=B*A
B=fi/A
B=3000/.25
B=12000
B=fi/A
B=3000/.25
B=12000
Alok kumar mishra said:
1 decade ago
Given:
Area = 0.25m^2.
flux = 3000*10^-6.
flux = magnetic flux density*area.
mfd = flux/area.
mfd = 3000*10^-6/.25.
mfd = 12000 ut.
Area = 0.25m^2.
flux = 3000*10^-6.
flux = magnetic flux density*area.
mfd = flux/area.
mfd = 3000*10^-6/.25.
mfd = 12000 ut.
Shreya said:
1 decade ago
So simple flux density means flux per unit area.
Pooh... said:
1 decade ago
What is the flux?
Nemai said:
1 decade ago
Flux density = Wb/m2.
Mohammad saad said:
1 decade ago
Simple flux density means flux per unit area.
mfd = flux/area.
mfd = flux/area.
Ankita anmol said:
1 decade ago
Mag.flux density = flux/unit area.
REX K B ANDOH said:
1 decade ago
Magnetic flux density, B = Magnetic flux,(PHI)/Area, A.
= 3000*10^-6/0.25.
= 12000 UT.
= 3000*10^-6/0.25.
= 12000 UT.
MANOJ said:
1 decade ago
MAGNETIC FLUX DENSITY = MAGNETIC FLUX/AREA.
B = 3000*10^-6/0.25 = 12000 MICRO WEBER/M^2.
B = 3000*10^-6/0.25 = 12000 MICRO WEBER/M^2.
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