# Electronics - Magnetism and Electromagnetism - Discussion

Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 3)
3.
What is the flux density of a magnetic field whose flux is 3000 µWb and cross-sectional area is 0.25 m2?
12,000 T
83,330 T
0 T
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Syed Shakeeb said:   1 year ago
B = H/A.
B = 3000Î¼/0.25,
B = 12000Î¼T.

Abdihalim Abdinor said:   4 years ago
Solution:

Flux = magnetic field/cross-sectional area.
= 3000/.25.
=12000μT.

Diptikanta sahu said:   5 years ago
Here, D=B/A,
=3000/0.25.

Anurag mishra said:   6 years ago
Q= B/A,
= 3000/0.25.
= 12000 micro-tesla.

Samir ali said:   6 years ago
Two type's of flux density. They are:
1) Magnetic flux density.
2) Electric flux density.

For magnetic flux density:
B(flux density) = Q(flux)/A(area).

For electric flux density:
D(flux density) = c/area.

Kainat.. said:   8 years ago
The flux passing through unit area gives flux density.

MANOJ said:   8 years ago
MAGNETIC FLUX DENSITY = MAGNETIC FLUX/AREA.

B = 3000*10^-6/0.25 = 12000 MICRO WEBER/M^2.

REX K B ANDOH said:   8 years ago
Magnetic flux density, B = Magnetic flux,(PHI)/Area, A.

= 3000*10^-6/0.25.

= 12000 UT.

Ankita anmol said:   8 years ago
Mag.flux density = flux/unit area.