Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - Filling the Blanks (Q.No. 9)
9.
The average value of the output voltage from the circuit in the given circuit equals ___.
Discussion:
15 comments Page 1 of 2.
Sheikh said:
9 years ago
How .367v came?
(1)
Sriniketan said:
1 decade ago
Ans 6.37V. i.e. Option D
Sol:
N2/N1=V2/V1 ==> 1/16=V2/160 ==> V2=10 VOLTS.
OUTPUT OF BRIDGE RECTIFIER IS 0.637V==> 0.637*10=6.37volts
Sol:
N2/N1=V2/V1 ==> 1/16=V2/160 ==> V2=10 VOLTS.
OUTPUT OF BRIDGE RECTIFIER IS 0.637V==> 0.637*10=6.37volts
Vinay said:
1 decade ago
We need to consider 1.4v drop for silicon. So answer is 5.48v.
Vuyisan said:
1 decade ago
Vs = 10v, V = 10-1.4 = 8.6v. Therefore,
Vav = Vdc = 8.6*0.636.
= 5.47v.
Vav = Vdc = 8.6*0.636.
= 5.47v.
Sndhya rajbhar said:
9 years ago
The accurate answer is 5.47v.
Mani said:
9 years ago
I think the circuit of the given bridge rectifier is wrong (ie diode direction).
Rohini said:
9 years ago
Answer should be 0V because the directions of the diode are reversed which cannot active in either cycle off into rectifier circuit, therefore the answer is 0V.
Lonne said:
9 years ago
The diode arrangement outputs 0V on either cycle. During the positive half, all diodes are open. During the second half, all are short, creating zero potential on the load resistor.
J crompton said:
8 years ago
V=100 1times 60 would become v2 can be divided or multiplied by the same way. The prime number is 6.
James said:
8 years ago
It's actually 2.74v. 10v-1.4 = 8.6 8.6/pi = 2.74v.
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