Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - Filling the Blanks (Q.No. 9)
9.
The average value of the output voltage from the circuit in the given circuit equals ___.
Discussion:
15 comments Page 1 of 2.
Manoj said:
7 years ago
The Answer should be zero.
Ciara said:
7 years ago
It must be C. 0 V because on that configuration, current will either not pass through the diodes or be cancelled out for the two cycles.
Natnael awel said:
8 years ago
The actual answer is 5.48. 10v - 1.4 = 8.6(2)/pi=5.48.
Masud Alom said:
8 years ago
0V because diode direction is wrong.
Manohar Arekar said:
8 years ago
Bridge rectifier circuit in diode direction is wrong.
James said:
8 years ago
It's actually 2.74v. 10v-1.4 = 8.6 8.6/pi = 2.74v.
J crompton said:
8 years ago
V=100 1times 60 would become v2 can be divided or multiplied by the same way. The prime number is 6.
Sheikh said:
9 years ago
How .367v came?
(1)
Lonne said:
9 years ago
The diode arrangement outputs 0V on either cycle. During the positive half, all diodes are open. During the second half, all are short, creating zero potential on the load resistor.
Rohini said:
9 years ago
Answer should be 0V because the directions of the diode are reversed which cannot active in either cycle off into rectifier circuit, therefore the answer is 0V.
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