Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 20)
20.
What is the current through the zener diode?
Discussion:
11 comments Page 1 of 2.
Priyanka rajput said:
1 decade ago
Vs = 13v
Vz = 6v
I = (Vs - Vz) / R
= (13-6)/1
= 7 mA
Vz = 6v
I = (Vs - Vz) / R
= (13-6)/1
= 7 mA
JYOTIRMOY MANTA said:
1 decade ago
Vs = 13 volt.
Vz = 6 volt.
so, I = Vs-Vz/R.
= 13-6/1000.
= 7/1000.
= 0.007A.
= 7mA.
Vz = 6 volt.
so, I = Vs-Vz/R.
= 13-6/1000.
= 7/1000.
= 0.007A.
= 7mA.
Virajsinh said:
1 decade ago
Vs = 13 V.
Vz = 6 V.
I = 13-6/1k.
= 7/1k.
= 0.007 A.
= 7 mA.
Vz = 6 V.
I = 13-6/1k.
= 7/1k.
= 0.007 A.
= 7 mA.
U panda said:
1 decade ago
If Vout = 6v then ans is 7mA.
If Vz(zener voltage) is 6v then answer is 19mA.
Terminal 1 is +ve and terminal 2 is -ve.
If Vz(zener voltage) is 6v then answer is 19mA.
Terminal 1 is +ve and terminal 2 is -ve.
(1)
Mckamo said:
1 decade ago
I = (Vs - Vz)/R.
= (13-6)/1.
= 7 mA.
= (13-6)/1.
= 7 mA.
DINESH JAGTAP SSIERAS RAHATA said:
10 years ago
I = (Vs-Vz)/R = (13-6)/1 = 7 mA.
Abhi said:
9 years ago
I = (Vs - Vz)/R in K.
I = (13 - 6)/(1 * 10^3).
I = 7mA.
I = (13 - 6)/(1 * 10^3).
I = 7mA.
(1)
ABC said:
9 years ago
V = IR.
(13 - 6) = I000 R,
7 = 1000 R,
R = 0.007 A,
R = 7mA.
(13 - 6) = I000 R,
7 = 1000 R,
R = 0.007 A,
R = 7mA.
Nandu said:
9 years ago
By applying KVL rule.
V = IR.
-13 + 1000I+ 6 = 0,
I = 7/1000 = 7 mA.
V = IR.
-13 + 1000I+ 6 = 0,
I = 7/1000 = 7 mA.
Digvijay tambe said:
9 years ago
Vs = 13v.
Vz = 6v.
I = (Vs - Vz) / R,
= (13 - 6)/1,
= 7 mA.
Vz = 6v.
I = (Vs - Vz) / R,
= (13 - 6)/1,
= 7 mA.
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