Discussion :: Diodes and Applications - General Questions (Q.No.4)
What is wrong with this diode?
Answer: Option C
No answer description available for this question.
|Jyoti Kushwaha said: (Sep 13, 2011)|
|Diode is in revers biased and hence reflecting the resistance in Megohm. It is normal behavior of a diode, nothing is wrong with Diode. So answer should be [C] nothing.|
|Arvind Kumar said: (Nov 28, 2011)|
|Diode is in reverse biased so it provide higher resistance,so it is normal behavior of diode,so nothing wrong with diode so answer is [c]|
|Pawan said: (Dec 28, 2011)|
|Since the negative terminal connected to p side the diode must be open circuited.|
|Puneet Thakral said: (Jan 5, 2012)|
|Answer [c] is correct. But actual reason behind this we are using multimeter not a voltage source or excitation source so neither it is in the state of forward bias nor reverse bias it acting as a normal component in which we don't apply any input.
So answer[c] is correct.
|Pavani said: (Feb 25, 2012)|
|Puneet thakral explaination is correct.|
|Vshwas Choudhary said: (Mar 18, 2012)|
|DIODE neither reverse bias nor forward bias. The reason behind is no source (voltage or current) connected. So diode act as a normal component.
So answer "C" is correct.
|Sjceian said: (Jul 13, 2012)|
|Diode is reverse biased. So, there might be no fault with the diode.|
|Akanksha Rao said: (Oct 10, 2013)|
|Option c is correct because here we are not using the voltage or current devices so diode is not reverse bias as well as not in forward biased so there is nothing wrong with diode.|
|Trishul said: (Feb 17, 2014)|
|In a multimeter we can check resistance of any component. To find resistance it applies some excitation (voltage) across component, then some current flows.
Therefore it calculate R=V/I. In here diode n terminal will have more +ve than p terminal. Therefore reverse biased. Some reverse current(Io) will flows (not open). Resistance =v/Io.
|Ravina Jain said: (Oct 31, 2014)|
|Answer C is correct because diode without any input acts as a normal component and it is in reverse bias according to connection as shown above so reverse bias gives high resistance.|
|Hassan said: (Mar 28, 2015)|
|In reverse bias diode act like this, is its normal behavior nothing wrong with diode.|
|Gayatri said: (Dec 16, 2015)|
|When diode is connected in reverse bias, it shows high impedance because it acts like an open circuit.|
|Abhijit said: (Aug 21, 2016)|
|The diode is not any bias since we are not providing any energy source, but when the configuration of the circuit is like this it will show the reverse bias resistance of the diode which may be infinity (ideal) or may be a very high value (for the practical diode) in mega-ohm range. So option C is correct.|
|S.L.Kulayappa said: (Feb 3, 2017)|
|Since, there is no source to ON the diode, then there is no current.|
|Harshal Darbhe said: (Oct 19, 2017)|
|Nothing, because no supply is given to diode so how decided it will go into reverse or forward biased. So, option C is right.|
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