Electronics - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 13)
13.
If an open capacitor is checked with an ohmmeter, the needle will:
stay on zero
stay on infinity
move from zero to infinity
move from infinity to zero
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Numeo said:   4 years ago
Since an ohmmeter uses its internal battery to measure the resistance by applying a small amount of DC current, Xc would be infinite because the voltage provided by a battery has no frequency thus 1/(2*pi*0*c) = infinite).

Seshendra said:   1 decade ago
We know that the capacitive reactance is 1/(2*pi*f*c)... Given that the capacitor is free from a source... So frequency applied for that capacitor is 0... So 1/(2*pi*0*c)=infinity...

ARCHANA said:   8 years ago
Actually, we know capacitive reactance is 1/2*π*f*c. Here applied frequency is zero. So capacitive reactance is infinity.

Shaan said:   1 decade ago
But Capacitor at instant t=0 - works like a short ? Then As per transient analysis it should move from 0 to infinity.

Gayu said:   1 decade ago
At a given condition, if the capacitor was charged it makes infinity, else zero. It depends upon the charge.

Meow said:   6 years ago
It should be from zero to infinity (option C). At time=inf is only the time your Xc would equal to infinite.

Urajanr said:   9 years ago
That's why the best is to use LCR where some level of frequency is pumped in to get the correct reading.

Shadan said:   8 years ago
Capacitor open means circuit open then resistance infinity so ohmmeter read infinute resistance.

ZERO said:   7 years ago
Infinity resistance because of dielectric metirial used in capacitor.

Syed Shakeeb said:   4 years ago
In an open circuit, resistance is infinity.

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