Electronics - Capacitors - Discussion


If an open capacitor is checked with an ohmmeter, the needle will:

[A]. stay on zero
[B]. stay on infinity
[C]. move from zero to infinity
[D]. move from infinity to zero

Answer: Option B


No answer description available for this question.

Seshendra said: (Nov 17, 2010)  
We know that the capacitive reactance is 1/(2*pi*f*c)... Given that the capacitor is free from a source... So frequency applied for that capacitor is 0... So 1/(2*pi*0*c)=infinity...

Shaan said: (Jun 24, 2012)  
But Capacitor at instant t=0 - works like a short ? Then As per transient analysis it should move from 0 to infinity.

Gayu said: (Jan 16, 2014)  
At a given condition, if the capacitor was charged it makes infinity, else zero. It depends upon the charge.

Urajanr said: (Apr 25, 2016)  
That's why the best is to use LCR where some level of frequency is pumped in to get the correct reading.

Archana said: (Dec 13, 2017)  
Actually, we know capacitive reactance is 1/2*π*f*c. Here applied frequency is zero. So capacitive reactance is infinity.

Shadan said: (Mar 15, 2018)  
Capacitor open means circuit open then resistance infinity so ohmmeter read infinute resistance.

Zero said: (Mar 26, 2019)  
Infinity resistance because of dielectric metirial used in capacitor.

Meow said: (Dec 9, 2019)  
It should be from zero to infinity (option C). At time=inf is only the time your Xc would equal to infinite.

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