Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 13)
13.
If an open capacitor is checked with an ohmmeter, the needle will:
Discussion:
10 comments Page 1 of 1.
Syed Shakeeb said:
4 years ago
In an open circuit, resistance is infinity.
Numeo said:
4 years ago
Since an ohmmeter uses its internal battery to measure the resistance by applying a small amount of DC current, Xc would be infinite because the voltage provided by a battery has no frequency thus 1/(2*pi*0*c) = infinite).
Meow said:
6 years ago
It should be from zero to infinity (option C). At time=inf is only the time your Xc would equal to infinite.
ZERO said:
7 years ago
Infinity resistance because of dielectric metirial used in capacitor.
Shadan said:
8 years ago
Capacitor open means circuit open then resistance infinity so ohmmeter read infinute resistance.
ARCHANA said:
8 years ago
Actually, we know capacitive reactance is 1/2*π*f*c. Here applied frequency is zero. So capacitive reactance is infinity.
Urajanr said:
9 years ago
That's why the best is to use LCR where some level of frequency is pumped in to get the correct reading.
Gayu said:
1 decade ago
At a given condition, if the capacitor was charged it makes infinity, else zero. It depends upon the charge.
Shaan said:
1 decade ago
But Capacitor at instant t=0 - works like a short ? Then As per transient analysis it should move from 0 to infinity.
Seshendra said:
1 decade ago
We know that the capacitive reactance is 1/(2*pi*f*c)... Given that the capacitor is free from a source... So frequency applied for that capacitor is 0... So 1/(2*pi*0*c)=infinity...
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