Electronics - Capacitors - Discussion

Xc=i/2*pi*f*c
at high frequency Xc is small.

Xc= 1/(2*pi*f*C)
Also, applied voltage V= Vc + Vr
At low frequency, 1/f is large and hence impedance offered by capacitor is also large. So, voltage drop woould be considerable across it.
On the other hand, at high frequency, 1/f gets small and hence capacitive reactance also small. Major voltage drop takes place across the resistor, or better call load.
Thus, at higher frequencies, we are getting Output voltage more close to the input. So, it is a high pass filter.

This is also diferentiator.

That is right. At high frequency that capacitor allows all current flow. Then this current flow will intern produce voltage drop in the load resistor R1. But at low frequency the capacitor give more resistance to the current flow.

I Agree with ritu

Xc=i/2*pi*f*c
at high frequency Xc is small.

As capacitor allows high frequency to pass and low to stop (dc).