Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 20)
20.
After a capacitor has charged for 1 tc, what percentage of current remains in the resistor?
Discussion:
17 comments Page 1 of 2.
Nitin said:
1 decade ago
The time required for a capacitor to rise from zero to 1-1/e (that is, 63.2%) of its final steady value when it varies with time t as 1 - e-kt. The time required for a capacitor to fall to 1/e (that is, 36.8%) of its initial value when it varies with time t as e-kt. Generally, the time required for an instrument to indicate a given percentage of the final reading resulting from an input signal. Also known as lag coefficient.
Pujitha said:
1 decade ago
If capacitor charges by 1tc(time constant).
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore,% of current remained in resistor = 100 - 63.6.
= 36.8%.
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore,% of current remained in resistor = 100 - 63.6.
= 36.8%.
Aryaan said:
9 years ago
But current remain same in series RC charging circuit.
I think it is voltages instead of current, 1tc = 63.2% of full voltages and at that time the voltages across the resistor are 36.8%.
So, it is voltages. If anyone agree with me?
I think it is voltages instead of current, 1tc = 63.2% of full voltages and at that time the voltages across the resistor are 36.8%.
So, it is voltages. If anyone agree with me?
Ashu k said:
6 years ago
If capacitor charges by 1tc (time constant).
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore % of current remained in resistor = 100 - 63.6.
= 36.8%.
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore % of current remained in resistor = 100 - 63.6.
= 36.8%.
(1)
Trxapeut said:
5 years ago
It = It(1-e^-t/T).
t=time,
T= time constant ,
It = total current.
If t = -T then It=I(1-e^-1),
It=0.632It ;
It-0.632It = 0.368It = 36.8% of current.
t=time,
T= time constant ,
It = total current.
If t = -T then It=I(1-e^-1),
It=0.632It ;
It-0.632It = 0.368It = 36.8% of current.
Shireen said:
1 decade ago
Capacitor charges upto 63. 2% of its final value in one tc. So 36.8% remaining. Hence current remaining in resistor is 36.8%.
Dufe said:
9 years ago
I was thought with voltage and not current.
Does it mean one can define time constant in terms of current?
Does it mean one can define time constant in terms of current?
Ali said:
7 years ago
What the value of V how it disappeared from the equation?
Archana Sasikumar said:
1 decade ago
How this V(1-e^-1) become 63.6? Can you please explain.
Ria said:
1 decade ago
@Archana,
e^-1 = 0.3678.
1-0.3678 = 0.6322.
= 63.2.
e^-1 = 0.3678.
1-0.3678 = 0.6322.
= 63.2.
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