Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 20)
20.
After a capacitor has charged for 1 tc, what percentage of current remains in the resistor?
Discussion:
17 comments Page 1 of 2.
Trxapeut said:
5 years ago
It = It(1-e^-t/T).
t=time,
T= time constant ,
It = total current.
If t = -T then It=I(1-e^-1),
It=0.632It ;
It-0.632It = 0.368It = 36.8% of current.
t=time,
T= time constant ,
It = total current.
If t = -T then It=I(1-e^-1),
It=0.632It ;
It-0.632It = 0.368It = 36.8% of current.
Ashu k said:
6 years ago
If capacitor charges by 1tc (time constant).
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore % of current remained in resistor = 100 - 63.6.
= 36.8%.
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore % of current remained in resistor = 100 - 63.6.
= 36.8%.
(1)
Ali said:
7 years ago
What the value of V how it disappeared from the equation?
Dufe said:
9 years ago
I was thought with voltage and not current.
Does it mean one can define time constant in terms of current?
Does it mean one can define time constant in terms of current?
Aryaan said:
9 years ago
But current remain same in series RC charging circuit.
I think it is voltages instead of current, 1tc = 63.2% of full voltages and at that time the voltages across the resistor are 36.8%.
So, it is voltages. If anyone agree with me?
I think it is voltages instead of current, 1tc = 63.2% of full voltages and at that time the voltages across the resistor are 36.8%.
So, it is voltages. If anyone agree with me?
Ria said:
1 decade ago
@Archana,
e^-1 = 0.3678.
1-0.3678 = 0.6322.
= 63.2.
e^-1 = 0.3678.
1-0.3678 = 0.6322.
= 63.2.
Archana Sasikumar said:
1 decade ago
How this V(1-e^-1) become 63.6? Can you please explain.
Pujitha said:
1 decade ago
If capacitor charges by 1tc(time constant).
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore,% of current remained in resistor = 100 - 63.6.
= 36.8%.
Vc=V(1-e^-t/rc).
Here, t = 1 rc.
=> Vc=V(1-e^-1).
=> Vc=63.6.
Therefore,% of current remained in resistor = 100 - 63.6.
= 36.8%.
Jagat said:
1 decade ago
100% - 63.2% = 36.8 %..........
very simple
very simple
Shireen said:
1 decade ago
Capacitor charges upto 63. 2% of its final value in one tc. So 36.8% remaining. Hence current remaining in resistor is 36.8%.
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