Electronics - Basic Op-Amp Circuits - Discussion
Discussion Forum : Basic Op-Amp Circuits - General Questions (Q.No. 2)
2.
The formula 
shows that for a given capacitor, if the voltage changes at a constant rate with respect to time, the current will
shows that for a given capacitor, if the voltage changes at a constant rate with respect to time, the current willDiscussion:
12 comments Page 1 of 2.
Vimal said:
1 decade ago
Integral (Icdt/C) = Vc
SO dVc/dt=Ic/t...Constant
SO dVc/dt=Ic/t...Constant
Pols said:
1 decade ago
Capacitor is open in dc.
Yugandhar said:
1 decade ago
dv/dt=k then v=kt;
Substitute.. i=ktC/t;
i=kC;
i=constant;
Substitute.. i=ktC/t;
i=kC;
i=constant;
Shiva prakash said:
1 decade ago
n^2=a^2+r^2
Vj tayal said:
1 decade ago
Voltage changes at const rate means with time v/t will be const and hence I is const.
Rama charan said:
1 decade ago
Since voltage changes with time, so overall ratio (V/t) will be constant.
Mervin said:
1 decade ago
In case of capacitor the there will be no change in current for the sudden change in voltage.
Ayush kumar srivastav said:
1 decade ago
Since voltage is change with respect to time then we say that the over all ratio is (v/t) will be constant.
Priyanka said:
1 decade ago
Since voltage change with time, so overall ratio (v/t) will be constant. i.e current will be constant.
Anomie said:
6 years ago
Voltage is constant C is constant Ic is constant with time.
But when Ic is C(dv/dt),
Then Ic is going to change with time to 5T.
But when Ic is C(dv/dt),
Then Ic is going to change with time to 5T.
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