Electronics  Basic OpAmp Circuits  Discussion
Discussion :: Basic OpAmp Circuits  General Questions (Q.No.2)
2. 
The formula shows that for a given capacitor, if the voltage changes at a constant rate with respect to time, the current will 
[A]. 
increase  [B]. 
decrease  [C]. 
be constant  [D]. 
decrease logarithmically 
Answer: Option C
Explanation:
No answer description available for this question.

Vimal said:
(Apr 7, 2011)


Integral (Icdt/C) = Vc
SO dVc/dt=Ic/t...Constant 
Pols said:
(May 24, 2011)


Capacitor is open in dc. 
Yugandhar said:
(Aug 16, 2011)


dv/dt=k then v=kt;
Substitute.. i=ktC/t;
i=kC;
i=constant; 
Shiva Prakash said:
(Aug 25, 2011)


n^2=a^2+r^2 
Vj Tayal said:
(May 12, 2012)


Voltage changes at const rate means with time v/t will be const and hence I is const. 
Rama Charan said:
(May 24, 2012)


Since voltage changes with time, so overall ratio (V/t) will be constant. 
Mervin said:
(Feb 11, 2013)


In case of capacitor the there will be no change in current for the sudden change in voltage. 
Ayush Kumar Srivastav said:
(Aug 27, 2013)


Since voltage is change with respect to time then we say that the over all ratio is (v/t) will be constant. 
Priyanka said:
(Dec 12, 2014)


Since voltage change with time, so overall ratio (v/t) will be constant. i.e current will be constant. 
Anomie said:
(May 24, 2019)


Voltage is constant C is constant Ic is constant with time.
But when Ic is C(dv/dt),
Then Ic is going to change with time to 5T. 
Edozi said:
(Sep 12, 2019)


Yes, since the situation is 'voltage changes at constant rate' the current will be constant also because they are proportional with each other. 