Electronics - Basic Op-Amp Circuits - Discussion

2. 

The formula mcq19_1008_1.gif shows that for a given capacitor, if the voltage changes at a constant rate with respect to time, the current will

[A]. increase
[B]. decrease
[C]. be constant
[D]. decrease logarithmically

Answer: Option C

Explanation:

No answer description available for this question.

Vimal said: (Apr 7, 2011)  
Integral (Icdt/C) = Vc

SO dVc/dt=Ic/t...Constant

Pols said: (May 24, 2011)  
Capacitor is open in dc.

Yugandhar said: (Aug 16, 2011)  
dv/dt=k then v=kt;

Substitute.. i=ktC/t;

i=kC;

i=constant;

Shiva Prakash said: (Aug 25, 2011)  
n^2=a^2+r^2

Vj Tayal said: (May 12, 2012)  
Voltage changes at const rate means with time v/t will be const and hence I is const.

Rama Charan said: (May 24, 2012)  
Since voltage changes with time, so overall ratio (V/t) will be constant.

Mervin said: (Feb 11, 2013)  
In case of capacitor the there will be no change in current for the sudden change in voltage.

Ayush Kumar Srivastav said: (Aug 27, 2013)  
Since voltage is change with respect to time then we say that the over all ratio is (v/t) will be constant.

Priyanka said: (Dec 12, 2014)  
Since voltage change with time, so overall ratio (v/t) will be constant. i.e current will be constant.

Anomie said: (May 24, 2019)  
Voltage is constant C is constant Ic is constant with time.
But when Ic is C(dv/dt),
Then Ic is going to change with time to 5T.

Edozi said: (Sep 12, 2019)  
Yes, since the situation is 'voltage changes at constant rate' the current will be constant also because they are proportional with each other.

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