Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
34 comments Page 2 of 4.
Manjeet said:
1 decade ago
Vo = 5(Vi/16)
= 5(5/16)
= 1.5625
4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
= 5(5/16)
= 1.5625
4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
SUMIT SHAH said:
1 decade ago
Main equation is,
Vo= Vref * (b0*2^(-1)+b1*2^(-2)+....)
Vo= 5 * (1*2^(-1)+0*2^(-2)+1*2^(-3)+0*2^(-4))
Vo=3.125V
Vo= Vref * (b0*2^(-1)+b1*2^(-2)+....)
Vo= 5 * (1*2^(-1)+0*2^(-2)+1*2^(-3)+0*2^(-4))
Vo=3.125V
Nisha said:
1 decade ago
In case of inverting, Vo = -1.5625 V.
In case of non-inverting, Vo = 3.125V.
So the given answer is correct.
In case of non-inverting, Vo = 3.125V.
So the given answer is correct.
Vishnu said:
4 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Pradeep sharma said:
6 years ago
It should be 1.5 because it is resolution * decimal equivalent
And it is 4 bit dac so 2^n =16.
And it is 4 bit dac so 2^n =16.
AL said:
3 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.
Sundar said:
1 decade ago
A 4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Iuuu said:
9 years ago
Formula = Vref/2^n(msb bit * 2^0 + nextbit * 2^1 + nextbit * 2^2 + lsb bit * 2^3).
Vimal said:
1 decade ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).
Kiran said:
1 decade ago
It can b solved as =ref. voltage * binary equivalent/ total no of steps.
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