Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
35 comments Page 2 of 4.
Panda said:
4 years ago
If the input code is 0101 then the answer should be 1.5625 volts. If we chose from the answer side then the input code should be 1010.
(1)
Manjeet said:
1 decade ago
Vo = 5(Vi/16)
= 5(5/16)
= 1.5625
4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
= 5(5/16)
= 1.5625
4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
SUMIT SHAH said:
1 decade ago
Main equation is,
Vo= Vref * (b0*2^(-1)+b1*2^(-2)+....)
Vo= 5 * (1*2^(-1)+0*2^(-2)+1*2^(-3)+0*2^(-4))
Vo=3.125V
Vo= Vref * (b0*2^(-1)+b1*2^(-2)+....)
Vo= 5 * (1*2^(-1)+0*2^(-2)+1*2^(-3)+0*2^(-4))
Vo=3.125V
Nisha said:
1 decade ago
In case of inverting, Vo = -1.5625 V.
In case of non-inverting, Vo = 3.125V.
So the given answer is correct.
In case of non-inverting, Vo = 3.125V.
So the given answer is correct.
Vishnu said:
5 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Pradeep sharma said:
7 years ago
It should be 1.5 because it is resolution * decimal equivalent
And it is 4 bit dac so 2^n =16.
And it is 4 bit dac so 2^n =16.
(1)
AL said:
4 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.
Sundar said:
1 decade ago
A 4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Iuuu said:
10 years ago
Formula = Vref/2^n(msb bit * 2^0 + nextbit * 2^1 + nextbit * 2^2 + lsb bit * 2^3).
Vimal said:
2 decades ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).
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