Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 3)
3.
A binary-weighted digital-to-analog converter has an input resistor of 100 k
. If the resistor is connected to a 5 V source, the current through the resistor is:
. If the resistor is connected to a 5 V source, the current through the resistor is:50 
A
A5 mA
500 A
A50 mA
Discussion:
9 comments Page 1 of 1.
Raja said:
1 decade ago
db/dv==100/5=20
db+30
20+30=50
db+30
20+30=50
Anshu said:
1 decade ago
Please explain, where you get 30 ?
Pandhala raju said:
1 decade ago
I=V/R;
=5/100K ohms
=0.05m amps
=50micro amps
=5/100K ohms
=0.05m amps
=50micro amps
Pkansal2105@yahoo.in said:
1 decade ago
I=V/R
=5/100000
=.05mA
=50 microA
=5/100000
=.05mA
=50 microA
Ilaiyaraja said:
1 decade ago
I=V/R
I/P resister has 100k=100000,k=1000
resister has 5v,v=5
I=5/100000
I=.00005,micro amp=10^-6
I=50microA
I/P resister has 100k=100000,k=1000
resister has 5v,v=5
I=5/100000
I=.00005,micro amp=10^-6
I=50microA
Gopal prasad said:
1 decade ago
R=100 k
V=5v
I=V/R
=5v/100k
=0.05 mA
=50 microA
V=5v
I=V/R
=5v/100k
=0.05 mA
=50 microA
(1)
Karunakaran.R said:
1 decade ago
R = 100*10^3.
V = 5v.
I = V/R.
= 5/100*10^3.
= 50*10^-6.
= 50(micro)Ans.
V = 5v.
I = V/R.
= 5/100*10^3.
= 50*10^-6.
= 50(micro)Ans.
Dickson K Mussa said:
9 years ago
According to Ohms law.
V = IR.
V = IR.
SKP said:
6 years ago
What was the significance of "binary-weighted digital-to-analog converter "?
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