Electronics - Analog and Digital Converters - Discussion

3. 

A binary-weighted digital-to-analog converter has an input resistor of 100 komega.gif. If the resistor is connected to a 5 V source, the current through the resistor is:

[A]. 50 mu.gifA
[B]. 5 mA
[C]. 500 mu.gifA
[D]. 50 mA

Answer: Option A

Explanation:

No answer description available for this question.

Raja said: (May 28, 2011)  
db/dv==100/5=20


db+30

20+30=50

Anshu said: (Jul 25, 2011)  
Please explain, where you get 30 ?

Pandhala Raju said: (Aug 29, 2011)  
I=V/R;
=5/100K ohms
=0.05m amps
=50micro amps

Pkansal2105@Yahoo.In said: (Dec 30, 2011)  
I=V/R
=5/100000
=.05mA
=50 microA

Ilaiyaraja said: (Jan 10, 2012)  
I=V/R
I/P resister has 100k=100000,k=1000
resister has 5v,v=5
I=5/100000
I=.00005,micro amp=10^-6
I=50microA

Gopal Prasad said: (May 11, 2012)  
R=100 k
V=5v
I=V/R
=5v/100k
=0.05 mA
=50 microA

Karunakaran.R said: (Sep 28, 2014)  
R = 100*10^3.
V = 5v.

I = V/R.
= 5/100*10^3.
= 50*10^-6.
= 50(micro)Ans.

Dickson K Mussa said: (Dec 19, 2016)  
According to Ohms law.

V = IR.

Skp said: (Jun 14, 2019)  
What was the significance of "binary-weighted digital-to-analog converter "?

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