Electronics - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - Filling the Blanks (Q.No. 10)
10.
A peak current of 12.5 mA is equivalent to ___.
Discussion:
5 comments Page 1 of 1.
Rajnish Sinha said:
1 decade ago
Formula : Imax = 1.57* I(avg)
Here, Find the I(avg) = Imax/1.57
= 12.5/ 1.5
= 7.96
Here, Find the I(avg) = Imax/1.57
= 12.5/ 1.5
= 7.96
Guru said:
1 decade ago
@Jagadeesh.
Iav = 2Im/pi.
Im = (pi/2)Iav.
Im = 1.57Iav.
Iav = 2Im/pi.
Im = (pi/2)Iav.
Im = 1.57Iav.
Ritu said:
1 decade ago
Imax= 1.57* I(avg)
so, 12.5/ 1.57 = 7.96
so, 12.5/ 1.57 = 7.96
Shainen said:
1 decade ago
Please write the formulae atleast.
Jagadeesh said:
1 decade ago
1.57 refers?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers