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Electronics - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - Filling the Blanks (Q.No. 10)
Alternating Current and Voltage
10.
A peak current of 12.5 mA is equivalent to ___.
an rms value of 25 mA
an average value of 12.5 mA
a peak-to-peak value of 6.25 mA
an average value of 7.96 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.
Guru said:   1 decade ago
@Jagadeesh.

Iav = 2Im/pi.

Im = (pi/2)Iav.

Im = 1.57Iav.
Jagadeesh said:   1 decade ago
1.57 refers?
Rajnish Sinha said:   1 decade ago
Formula : Imax = 1.57* I(avg)
Here, Find the I(avg) = Imax/1.57
= 12.5/ 1.5
= 7.96
Ritu said:   1 decade ago
Imax= 1.57* I(avg)

so, 12.5/ 1.57 = 7.96
Shainen said:   1 decade ago
Please write the formulae atleast.
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