Circuit Simulator - Sawtooth Wave Generator

Sawtooth Wave Generator
Sawtooth Wave Generator
Circuit Description:
This circuit is an oscillator that generates a sawtooth wave. It's basically the same circuit as the triangle wave oscillator, except that the resistor in series with the capacitor has been replaced by two resistors, each paired with a diode going in opposite directions. For the first half of the cycle, the capacitor charges through a 40k resistor, and for the other half, it quickly discharges through a 5k resistor.

Discussion:
16 comments Page 1 of 2.

Hasi said:   1 decade ago
What is the application of sawtooth?
(2)

Vignesh said:   1 decade ago
@Author.

I tried this circuit. Its not producing waveform. I tried with different values.
(7)

Durga said:   1 decade ago
I tried the same circuit in multisim but the output is not coming may I know the reason?
(2)

Amresh said:   1 decade ago
How saw tooth wave works?
(3)

PluralChimera0 said:   1 decade ago
The sawtooth waves only real use is for sound synthesis. Hook the output up to an 8 ohm speaker and connect the speaker to ground to hear a pure unfiltered sawtooth wave.
(1)

DIkSploogeeeeMcGee said:   1 decade ago
I don't get it. It only starts oscillating after you disconnect the power. I need constant power. Well I guess its because nothing is drawing current to theres no where for the electricity in the wires to go.
(2)

Eric said:   1 decade ago
What are the applications of the saw-tooth generator?
(6)

Pete said:   1 decade ago
Thanks for the diagram. I drew up the circuit in Orcad Capture and was able to run it fine. I changed the capacitor to a smaller value to increase the frequency. I am trying to design a circuit that produces a sawtooth at about 110-120 Hz to mimic the fundamental frequency of a male speaker.
I used Capture to generate a Fourier transform of the signal, and thought that the energy drops off pretty quick for what I want. I'm messing with different component values to try to decrease the dropoff.
I changed the 5k for a 2k, and the upper 40k for 80k, resulting in an even steeper slope in the fast component of the waveform. The Fourier transform resulted in an even bigger drop between the fundamental and the second harmonic, but the amplitude at higher frequencies seems to persist.
(7)

Saman said:   1 decade ago
I do not have waveform in the output! Why?
(2)

Prabha said:   1 decade ago
No voltage source input why?
(6)


Post your comments here:

Your comments will be displayed after verification.